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igor_vitrenko [27]
3 years ago
5

Can someone help me find the answer?

Mathematics
2 answers:
raketka [301]3 years ago
8 0

Answer:

AC=9 cm

ABC is not a right angled triangle

Step-by-step explanation:

AB=8cm

BC=5cm

22=AB+BC+AC

AC=22-8-5

AC=9

since AC is the longest,

using Pythagoras theorem

AC^2=BC^2+AB^2

9^2=8^2+5^2

81=64+25

81=89

therefore, it is not a right angled triangle

Gnesinka [82]3 years ago
3 0

Answer:

No it is not a right triangle.

Step-by-step explanation:

Use the Pythagorean theorem to answer this question

1. find the missing side

8+5+x=22

13+x=22

x=9

2. Plug what you know into the Pythagorean theorem

a^2 +b^2=c^2

8^2+5^2=9^2

(if this  is true then it is a right angle)

64+25=81

89≠81

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Answer:

x = 30°

The angles:

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Step-by-step explanation:

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The sum of all the angles in a triangle is 180°. So we can set up an equation for this question.

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2 years ago
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The daily average temperature in Santiago, Chile, varies over time in a periodic way that can be modeled approximately by a trig
natali 33 [55]

Answer:

a) the trigonometric function is;

y = 7.5 sin ( \frac{2 \pi}{365}t + \frac{337 \pi}{730})+ 21.5

b) y = 28.36^0 \ C    ( to two decimal places)

Step-by-step explanation:

This data can be represented by the sinusoidal function of the form :

\mathbf{y = A sin (Bt -C)+D}

where A = amplitude and which can be determined via the formula:

A = \dfrac{largest \ temperature -  lowest \ temperature}{2}

A = \dfrac{29-14}{2}

A = \dfrac{15}{2}

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where B = the frequency;

Since the data covers a period of 3 days ; then \dfrac{2 \pi}{B } =365

B = \dfrac{2 \pi}{365}   ( where 365 is the time period )

The vertical shift is found by the equation D;

D =  \frac{largest \ temperature + lowest \ temperature}{2}

D = \frac{29+14}{2}

D = 21.5

Replacing the values of A ; B and D into the above sinusoidal function; we have :

y = 7.5 sin (\frac{2 \pi}{365}t -C) + 21.5

From the question; when it is 7th of the year ( i.e January 7);

t =  7 and the temperature (y) = 29° C

replacing that too into the above equation; we have:

29= 7.5 sin (\frac{2 \pi}{365}*7 -C) + 21.5

29= 7.5 sin (\frac{14 \pi}{365} -C) + 21.5

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1=  sin (\frac{14 \pi}{365} -C)

sin^{-1}(1)=   (\frac{14 \pi}{365} -C)

\frac{\pi}{2}=   (\frac{14 \pi}{365} -C)

C=   (\frac{14 \pi}{365} -\frac{\pi}{2})

C=   (\frac{28 \pi- 365 \pi}{730} )

C=  \frac{-337 \pi}{730}

Thus; the trigonometric function is;

y = 7.5 sin ( \frac{2 \pi}{365}t + \frac{337 \pi}{730})+ 21.5

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y = 7.5 sin ( \frac{2 \pi}{365}*31+ \frac{337 \pi}{730})+ 21.5

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