Answer:
4
Step-by-step explanation:
First n(AUB)=n(E) - n((AUB)')
So n(AUB) = 40 - 6 = 34
Now all u hv to do is use the formulae,
n(AUB) = n(A) + n(B) - n(ANB)
So when u substitute above values,
34=22 + n(B) - 8
So,
n(B) = 4
Graphs like these (lines) come in the form y = mx + b where m is the slope and b is the y intercept. Y intercept is where the graph intersects the y axis so the value would be 5
You plug -x+16 in for y in x+4y=37 to get x after you multiply x+4y=37 by -1.
-x-4(-x+16)=-37
-x+4x-64=-37
3x-64=-37
3x=27
x=9
Then you plug 9 into either equation to get y.
y=-x+16
y=-(9)+16
y=7
x=9 and y=7
The complete question in the attached figure
we know that
(see the attached figure n 2 to understand the problem)[the surface area of one prism]=2*[x*x]+2*[x*y]+2*[x*y]----> 2x²+4xy
[the surface area of the sculpture]=2*[5*x*y]+2*[3*x*x]+2*[3*x*y]--> 6x²+16xy
now
<span>JD says the surface area of the sculpture is 4 times the surface area of one prism
</span>[the surface area of the sculpture]=4*(2x²+4xy)---> 8x²+16xy
we compare the value that JD says with the real value
(8x²+16xy) > (6x²+16xy)
the value that JD says is <span>greater in comparison with the real value
</span>This is because <span>JD should also subtract the areas of eight hidden surfaces.
the answer is
</span>
JD should also subtract the areas of eight hidden surfaces<span>
</span>