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Oksanka [162]
3 years ago
12

The difference of 44 and the square of n into a expression

Mathematics
1 answer:
Otrada [13]3 years ago
7 0

Answer:

44-\sqrt{n}

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Find the solution of y = 2x + 5 for x = 1.
Sholpan [36]

Answer:

(1, 7)

Step-by-step explanation:

Substitute x = 1 into the equation for the corresponding value of y

y = 2x + 5 = (2 × 1) + 5 = 2 + 5 = 7

Solution is (1, 7)

8 0
3 years ago
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Which equation represents the graphed function?
NemiM [27]
Y=1/4-2 is the correct answer. you go up one and over four. the y-intercept is -2
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I'll give u full brainlist if u do this!
alex41 [277]

Answer:

a. 54.75

b. 2.64

Step-by-step explanation:

6 0
2 years ago
Can two lines be drawn from a point not on a line that will meet the line at a right angle? at a 45° angle? explain each answer.
vichka [17]
I believe the the correct answer would be yes. Two lines can be drawn from a point that is not collinear with a certain line that will meet the line at a right angle or 90 degree angle and at an angle of 45 degrees. We can freely draw any line that would pass through a given point and would cross a given line at any direction giving us different angles and this would include a 90 and 45 degree angle.
5 0
2 years ago
Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).
Oduvanchick [21]
For two complex numbers z_1=re^{i\theta}=r(\cos\theta+i\sin\theta) and z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi), the product is

z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))

That is, you multiply the moduli and add the arguments. You have z_1=7e^{i40^\circ} and z_2=6e^{i145^\circ}, so the product is

z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}
3 0
2 years ago
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