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Sveta_85 [38]
3 years ago
11

Which value can be entered to cause the following code segment to display the message: "That number is acceptable." int number;

cin >> number; if (number > 10 && number < 100) cout << "That number is acceptable.\n"; else cout << "That number is not acceptable.\n";
Computers and Technology
1 answer:
sashaice [31]3 years ago
7 0

Answer:

11 & 99

Explanation:

if (number > 10 && number < 100 )

if number is 11 to 99

if user press any number in between them or 11 , 99

then cout will be

"That number is acceptable ."

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Determine whether the compound condition is True or False.
Vlada [557]

The  compound condition are:

  • 7<12 or 50!=10 is false
  • 7<12 and 50<50 is false
  • not (8==3) is true

<h3>What is compound condition?</h3>

A compound statement is known to be one that shows up as the body of another statement, e.g. as in if statement.

The  compound condition are:

  • 7<12 or 50!=10 is false
  • 7<12 and 50<50 is false
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Learn more about compound condition  from

brainly.com/question/18450679

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1 year ago
1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
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Which of the following sets of data would be presented best in a histogram.
anastassius [24]
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Answer:

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