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NISA [10]
3 years ago
8

Three dice are rolled. Let the random variable x represent the sum of the 3 dice. By assuming that each of the 63 possible outco

mes is equally likely, find the probability that x equals 11.
Mathematics
1 answer:
tamaranim1 [39]3 years ago
7 0
<h3>Answer:  1/8</h3>

In decimal form, 1/8 = 0.125 which converts to 12.5%

==================================================

Work Shown:

The 63 should be 6^3. There are 6 choices per slot, and 3 slots, so 6^3 = 216 different outcomes.

Here are all of the ways to add to 11 if we had 3 dice

  1. sum = 1+4+6 = 11
  2. sum = 1+5+5 = 11
  3. sum = 1+6+4 = 11
  4. sum = 2+3+6 = 11
  5. sum = 2+4+5 = 11
  6. sum = 2+5+4 = 11
  7. sum = 2+6+3 = 11
  8. sum = 3+2+6 = 11
  9. sum = 3+3+5 = 11
  10. sum = 3+4+4 = 11
  11. sum = 3+5+3 = 11
  12. sum = 3+6+2 = 11
  13. sum = 4+1+6 = 11
  14. sum = 4+2+5 = 11
  15. sum = 4+3+4 = 11
  16. sum = 4+4+3 = 11
  17. sum = 4+5+2 = 11
  18. sum = 4+6+1 = 11
  19. sum = 5+1+5 = 11
  20. sum = 5+2+4 = 11
  21. sum = 5+3+3 = 11
  22. sum = 5+4+2 = 11
  23. sum = 5+5+1 = 11
  24. sum = 6+1+4 = 11
  25. sum = 6+2+3 = 11
  26. sum = 6+3+2 = 11
  27. sum = 6+4+1 = 11

There are 27 ways to add to 11  using 3 dice. This is out of 216 total outcomes of 3 dice being rolled.

So, 27/216 = (1*27)/(8*27) = 1/8 is the probability of getting 3 dice to add to 11.

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Why?

The first thing we need to do is find the area of the triangle, we can to that by subtracting the area of ABCD from ACBE, then, we can use the formulas to calculate the area for both triangle and rectangle to find "f" and "g".

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Now, we can calculate "f" by using the formula to calculate the area of the triangle:

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