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MakcuM [25]
3 years ago
5

Write word problems that represent each way you can use a remainder in a division problem. Include solutions. PLEASE COULD YOU H

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Mathematics
2 answers:
babymother [125]3 years ago
4 0

Division Problem: 90 people were invited to the party.

1. How many tables are needed, if each table can seat 8 people?

2. How many tables will be completely full?

3. How many people will be at an incomplete table?

Solution:

You have that 90=8·11+2 (8 - divisor, 11 - quotient, 2 - remainder).

Since the quotient is 11, 12 tables are needed, 11 tables will be completely full and the last 12th table will be incomplete, only 2 people will be at this table.

Answer: 1. 12 tables, 2. 11 tables, 3. 2 people

Georgia [21]3 years ago
4 0
Lets say that 46 divided by 5 is 9 with a remaidnder of 1.First you have to multiply 9 with 5.Then take the reaminder and add it to the answer you get form multi pining 9 and 5.
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The sales tax on a piece of furniture that cost $450 was 28.13 . what was the percent sales tax?
inysia [295]
28.13÷450= .0625111

.0625111×100= 6.25111%
4 0
4 years ago
(3x-5)/(x-5)&gt;=0 <br> How do I get the answers for this problem?
Diano4ka-milaya [45]
\frac{3x-5}{x-5} > 0 

First, note that x is undefined at 5. / x ≠ 5
Second, replace the inequality sign with an equal sign so that we can solve it like a normal equation. / Your problem should look like: \frac{3x-5}{x-5} = 0
Third, multiply both sides by x - 5. / Your problem should look like: 3x - 5 = 0
Forth, add 5 to both sides. / Your problem should look like: 3x = 5
Fifth, divide both sides by 3. / Your problem should look like: x = \frac{5}{3}
Sixth, from the values of x above, we have these 3 intervals to test: 
x < \frac{5}{3}
\frac{5}{3} < x < 5
x > 5
Seventh, pick a test point for each interval. 

1. For the interval x < \frac{5}{3} :
Let's pick x - 0. Then, \frac{3x0-5}{0-5} > 0
After simplifying, we get 1 > 0 which is true.
Keep this interval.

2. For the interval \frac{5}{3} < x < 5:
Let's pick x = 2. Then, \frac{3x2-5}{2-5} > 0
After simplifying, we get -0.3333 > 0, which is false.
Drop this interval.

3. For the interval x > 5:
Let's pick x = 6. Then, \frac{3x6-5}{6-5} > 0
After simplifying, we get 13 > 0, which is ture.
Keep this interval.
Eighth, therefore, x < \frac{5}{3} and x > 5

Answer: x < \frac{5}{3} and x > 5

3 0
3 years ago
You flip a coin eight times. find the number of possible outcomes in the sample space.
nika2105 [10]
2( coin faces) 8( number of times)
6 0
3 years ago
You work for a printing company.Your machine can prine 80 posters per hour. You printed 600 posters. How many hours did you work
AlexFokin [52]
The amount of hours you worked would be 7.5, you divide 600 by 80.
7 0
3 years ago
Can u solve this problem in show your work
aksik [14]

Hey there!

We can solve this problem by doing PEMDAS, which lists:

Parentheses \\ Exponents \\ Multiplication \\  Division \\ Addition \\ Subtraction

We have in this equation

Parentheses \\ Exponents \\ Dvision

Let's sp;ve this equation now!

Parentheses ↓

(6 -3) = 3

Exponents ↓

3^2  = 9

Division ↓

\frac{36}{9}  = 9

Okay now , I show you the steps so it can be easier to solve!

\frac{36}{(6-3)^2} \\ \\  6-3 = 3 \\   \\ \frac{36}{3^2}  \\ \\ 3^2 = 9   \\  \\ \frac{36}{9} \\ \\ \\ \\ Answer: 4

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

5 0
3 years ago
Read 2 more answers
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