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gavmur [86]
3 years ago
15

What are the solutions of 2x2 + 16x + 34 = 0?

Mathematics
2 answers:
Anni [7]3 years ago
8 0
2x^2 + 16x + 34 = 0
x^2 + 8x + 17 = 0
x^2 + 8x + 16 = -17 + 16 = -1
(x + 4)^2 = -1
x + 4 = sqrt(-1) = ±i
x = -4 <span>±</span> i
Scorpion4ik [409]3 years ago
3 0

Answer:

\text{The solution is }x=-4\pm i

Step-by-step explanation:

Given the equation

2x^2+16x+34=0

we have to find the solutions of above equation

2x^2+16x+34=0

Comparing it with standard quadratic equation ax^2+bx+c=0

a=2, b=16, c=34

The solution is

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\frac{-16\pm \sqrt{16^2-4(2)(34)}}{2(2)}

x=\frac{-16\pm \sqrt{-16}}{4}

x=-4\pm i

\text{The solution is }x=-4\pm i

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