Question

What are the solutions of 2x2 + 16x + 34 = 0?

Answer 1

2x^2 + 16x + 34 = 0
x^2 + 8x + 17 = 0
x^2 + 8x + 16 = -17 + 16 = -1
(x + 4)^2 = -1
x + 4 = sqrt(-1) = ±i
x = -4 ± i

Answer 2

Answer:

$\text{The solution is }x=-4\pm i$

Step-by-step explanation:

Given the equation

$2x^2+16x+34=0$

we have to find the solutions of above equation

$2x^2+16x+34=0$

Comparing it with standard quadratic equation $ax^2+bx+c=0$

a=2, b=16, c=34

The solution is

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-16\pm \sqrt{16^2-4(2)(34)}}{2(2)}$

$x=\frac{-16\pm \sqrt{-16}}{4}$

$x=-4\pm i$

$\text{The solution is }x=-4\pm i$