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My name is Ann [436]
2 years ago
15

I need help please!:D

Mathematics
1 answer:
tatyana61 [14]2 years ago
4 0
3 4 6 jebdhdbdndjxbdjdjdbdudb
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Please help meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
Flura [38]

Answer:

#6 is 17 days

Step-by-step explanation:

This is how I answered it

1) 2750 = 550 + 125x

2) subtract 550 from each side

2750-550=2200

so the left over equation is:

2200 = 125x

3) divide each side by 125 to get x by itself

2200÷125= 17.6

4) you are left with: x = 17 days

6 0
3 years ago
The sum of the measures of the angles is 180. The sum of the measures of the second and third angles is two times the measure of
grigory [225]
<h2>60,47,73</h2>

Step-by-step explanation:

Let the first angle be a degrees

Let the second angle be b degrees

Let the third angle be c degrees

It is given that sum of angles is 180 degrees.

so,a+b+c=180                      ...(i)

It is given that sum of the measures of the second and third angles is two times the measure of the first angle.

b+c=2\times a                     ...(ii)

It is given that the third angle is 26 more than the second.

c=26+b                                ...(iii)

using (ii) and (iii),

b+b+26=2a

b+13=a

using (i),(ii) and (iii),

a+b+c=a+a-13+26+b=a+a-13+26+a-13=3a

3a=180

a=60

b=a-13=60-13=47

c=26+b=26+47=73

3 0
3 years ago
Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 144 millimeters,
valentinak56 [21]

Answer:

The probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample  means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean  is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

<em>μ</em> = 144 mm

<em>σ</em> = 7 mm

<em>n</em> = 50.

Since <em>n</em> = 50 > 30, the Central limit theorem can be applied to approximate the sampling distribution of sample mean.

\bar X\sim N(\mu_{\bar x}=144, \sigma_{\bar x}^{2}=0.98)

Compute the probability that the sample mean would differ from the population mean by more than 2.6 mm as follows:

P(\bar X-\mu_{\bar x}>2.6)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}} >\frac{2.6}{\sqrt{0.98}})

                           =P(Z>2.63)\\=1-P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 2.6 mm is 0.0043.

8 0
3 years ago
Suppose that 22 inches of wire costs 66 cents.
GaryK [48]

Answer:

51 cents for 17 inches of wire

Step-by-step explanation:

22 = 66

17 = x

22x = 66 * 17

22x = 1122

x = 51 cents

or

22 inches costs 66 cents

1 inch costs 3  cents (66 / 22 = 3  cents)

17 inches costs 51  cents (17 * 3 = 51 cents)

8 0
2 years ago
Which expression is equivalent to StartRoot 200 EndRoot?
Verdich [7]

Answer:

b)  √200 = 10√2

Step-by-step explanation:

Here, the given expression is: √200

Simplifying the given expression, we get:

200 = 2 x 2 x 2 x 5  x 5

⇒ 200  = (2)²  x (5) ²  x 2

Taking ROOT both sides, we get:\sqrt{200}  = \sqrt{(2)^{2}  \times (5)^{2}  \times  2}\\\implies \sqrt{200} = \sqrt{(2)^{2} } \times \sqrt{(5)^{2} } \times  \sqrt{(2) }  = 2 \times 5 \times \sqrt{2}\\ = 10 \sqrt {2}\\\implies \sqrt{200}  =  10 \sqrt {2}

Hence,   √200 = 10√2

5 0
3 years ago
Read 2 more answers
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