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4 years ago

Help (6)(-1)(-3)(10)(-2)

Mathematics

1 answer:

Sloan [31]4 years ago

4 0

Answer:

The answer is

Step-by-step explanation:

(6)(-1)(-3)(10)(-2)

Multiply the terms in the bracket

That's

(6)(-1) = - 6

(-3)(10) = - 30

So we have

(-6)(-30)(-2)

= 180( - 2)

= - 360

Hope this helps you

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Solve f (x)=3x+6 f(300)

sveta [45]

Answer:

$f(300)=906$

Step-by-step explanation:

$f(x)=3x+6\\\\f(300)=3(300)+6\\\\f(300)=900+6\\\\\boxed{f(300)=906}$

Hope this helps.

8 0

3 years ago

In 1934 there was an extreme drought and the Great Plains and the number 1,934 is the value of the nine and the hundredth place

WARRIOR [948]

It should be noted that No. the value of the 9 in the hundred place is not ten times the value of 3 in the tens place.

<h3>How to illustrate the information?</h3>

It should be noted that the value of 3 in 1934 is 30 and the value of 9 is 900.

1934 = 1000 + 900 + 30 + 4

Therefore the value of 9 will be:

= 30 × 3

Therefore, the the value of the 9 in the hundred place is 30 times the value of 3 in the tens place.

Learn more about place values on:

brainly.com/question/2041524

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5 0

2 years ago

The _____ is used to measure volume<br> 1) liter<br> 2) gram<br> 3) meter

tekilochka [14]

1 - liter
will be the answer

4 0

4 years ago

Read 2 more answers

Simplify the following expression <br>9/20 + 5/12

Artyom0805 [142]

<em>9/20+5/12=14/32/2 equals a over all 7/16</em>

4 0

4 years ago

Read 2 more answers

For which rational expression is 8 an excluded value ? check all that apply

denis23 [38]

<u>Answer:</u>

The correct answer options are C. $\frac{x^2+5}{x-8}$ and D. $\frac{x^2-x-56}{x^2-64}$ .

<u>Step-by-step explanation:</u>

The values which make the denominator equal to zero are called the excluded values.

Here, we can substitute 8 for x and check if it makes the denominator 0.

$\frac{x-8}{x+8} = \frac{8-8}{8+8} =\frac{0}{16} =0$

$\frac{x-2}{x^2-4} = \frac{8-2}{8^2-4} =\frac{6}{60} =\frac{1}{10}$

$\frac{x^2+5}{x-8} = \frac{8^2+5}{8-8} =\frac{69}{0}$

$\frac{x^2-x-56}{x^2-64} = \frac{8^2-8-56}{8^2-64} = \frac{0}{0} =0$

$\frac{8x^2-2}{x^2-16} = \frac{8(8)^2-2}{8^2-16} =\frac{510}{48}$

7 0

3 years ago