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3 years ago

The difference of 4 times a number and 7 is 21. Find the number.

Mathematics

2 answers:

ryzh [129]3 years ago

8 0

Answer:

The number is 7.

Step-by-step explanation:

Let, that number is $x$ .

According to the question,

$4\times x - 7 = 21$

$4\times x = 28\\x = 7$

USPshnik [31]3 years ago

3 0

Answer:

The number is 7.

Step-by-step explanation:

4n - 7 = 21 Add 7 on both sides

4n = 28 Isolate the variable by dividing 4 on both sides

n= 7

<h3>Hope this helps!!! </h3><h3>Please mark this as brainliest!!! </h3><h3>Thank You!!! </h3><h3>:)</h3>

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3 years ago

Read 2 more answers

If r and s are positive integers, is \small \frac{r}{s} an integer? (1) Every factor of s is also a factor of r. (2) Every prime

Yuri [45]

Answer:

If statement(1) holds true, it is correct that $\small \frac{r}{s}$ is an integer.

If statement(2) holds true, it is not necessarily correct that $\small \frac{r}{s}$ is an integer.

Step-by-step explanation:

Given two positive integers $r$ and $s$ .

To check whether $\small \frac{r}{s}$ is an integer:

Condition (1):

Every factor of $s$ is also a factor of $r$ .

$r \geq s$

Let us consider an example:

$s = 5^2 \cdot 2\\r = 5^3 \cdot 2^2$

$\dfrac{r}{s} = \dfrac{5^3\cdot2^2}{5^2\cdot2} = 10$

which is an integer.

Actually, in this situation $s$ is a factor of $r$ .

Condition 2:

Every prime factor of s is also a prime factor of r.

(But the powers of prime factors need not be equal as we are not given the conditions related to powers of prime factors.)

Let

$r = 2^2\cdot 5\\s =2^4\cdot 5$

$\dfrac{r}{s} = \dfrac{2^3\cdot5}{2^4\cdot5} = \dfrac{1}{2}$

which is not an integer.

So, the answer is:

If statement(1) holds true, it is correct that $\small \frac{r}{s}$ is an integer.

If statement(2) holds true, it is not necessarily correct that $\small \frac{r}{s}$ is an integer.

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