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3 years ago

HURRY !!!

Physics

2 answers:

nydimaria [60]3 years ago

6 0

A.
D.
G.
Hop this helps

storchak [24]3 years ago

6 0

Answer:

A.) The spheres develop opposite charges.

D.) Electrons move from sphere A to sphere B.

E.) The spheres are charged through conduction.

Explanation:

In the diagram, spheres A and B are in contact, so this method is charging by contact or conduction. The rod is negatively charged, thus it attracts the protons in A and repels it electrons. Which flow into sphere B when earthened, so that B becomes negatively charged. On separation of the spheres and then removal of the charged rod, sphere A would be positively charged. Thus spheres A and B possess opposite charges.

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The density of aluminum is 2.7 × 103 kg/m3 . the speed of longitudinal waves in an aluminum rod is measured to be 5.1 × 103 m/s.

andrey2020 [161]

<span>The speed of longitudinal waves, S, in a thin rod = âšYoung modulus / density , where Y is in N/m^2. So, S = âšYoung modulus/ density. Squaring both sides, we have, S^2 = Young Modulus/ density. So, Young Modulus = S^2 * density; where S is the speed of the longitudinal wave. Then Substiting into the eqn we have (5.1 *10^3)^2 * 2.7 * 10^3 = 26.01 * 10^6 * 2.7 *10^6 = 26.01 * 2.7 * 10^ (6+3) = 70.227 * 10 ^9</span>

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4 years ago

A bird flies 10 miles south, turns and flies 15 miles east. What distance did it fly.

vfiekz [6]

Answer:

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Explanation:

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3 years ago

A child throws a baseball upward with an initial velocity of 20 m/s. The child wants to throw the baseball at least as high as t

Umnica [9.8K]

When the ball starts its motion from the ground, its potential energy is zero, so all its mechanical energy is kinetic energy of the motion:
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3 years ago

On earth, two parts of a space probe weigh 14500 N and 4800 N. These parts are separated by a center-to-center distance of 18 m

Nastasia [14]

Answer:

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Therefore,

$m_{1} = \frac{14500}{9.81}$

$m_{1} = 1478.08 kg$

Similarly,

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$m_{2} = 489.29 kg$

Now, considering these two parts as uniform spherical objects

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Force between these two objects is given by:

$F = \frac{Gm_{1} m_{2}}{R^{2} }$

G= gravitational constant ( $6.67 * 10^{-11} m^{3} kg^{-1} s^{-2}$ )

$m_{1} , m_{2}$ = masses of the object

R= distance between their centres (in m)(18 m)

Substituiting all these values into the above formula

$F = 1.489*10^{-7} N$

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3 years ago

a block (mass 0.6kg) is released from rest at point A at the top of a ramp inclined at 36.9 degress above the horizontal. The bl

bija089 [108]

14.136 J as shown on the photo with two thought processes but overall same calculation

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3 years ago