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Elena-2011 [213]
1 year ago
5

Sam's job at the amusement park is to slow down and bring to a stop the boats in the log ride.

Physics
1 answer:
Mashcka [7]1 year ago
3 0

The amount of work which Sam does need to stop the boat is 784Joule  if boat mass  is 800kg and boat drift in 1.4m/sec.

We know that according to work-energy theorem, change in kinetic energy of the body from one speed to another is equivalent to amount of work done by all forces acting on the body.

So, here we can see that final speed of boat is =0m/sec since Sam need to stop it.

Initial speed of boat is 1.4m/sec.

Also, we know that kinetic energy is given by the below formula:

Kinetic energy=(1/2)mv²

where m is the mass of the body

and v is the speed of the body

Now, from work energy theorem, we get

=>W=(1/2)mv^2_2 - (1/2)mv^2_1

=>W=0-(1/2)×800×(1.4)²

=>W= - 400× 1.4 × 1.4

=>W = -400×1.96

=>W= -784Joule

Here negative sign denotes work has to done against the original motion of boat.

Hence, amount of work needs to be done by Sam is 784Joule.

To know more about work,visit here:

brainly.com/question/18094932

#SPJ4

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Which of these objects must have the greatest force acting on it? pls help fast
8_murik_8 [283]

Let's look at Newton's second law

  • F=ma

Force is directly proportional towards mass

If mass is more force will be more.

Between baseball and bowling ball Bowling ball has higher mass

So it would expert most force

Option D

8 0
2 years ago
At a certain altitude above the Earth's surface, the electric field has a magnitude of 135 V/m. How much energy is stored in 1.0
Paul [167]

Answer:

Explanation:

Given that,

Electric field E=135V/m

Energy stored in 1m³of air=?

The energy stored in an electric field is given as

u = ½ εo E²

Where

U is the energy stored

εo is permissivity and it value is 8.85×10^-12C²/N..m²

And E is the electric field

Then,

U=½×8.85×10^-12×135²

U=8.06×10^-8J/m³

Then, the energy stored in 1m³ of air is 8.06×10^-8 J/m³

4 0
3 years ago
The distance between two stations is 1995 Km. How much time will it take to cover the distance at an average speed of 19KM/hour
Flura [38]
105 hours or 4.375 days
5 0
4 years ago
Suppose you have a hypothesis you believe to be correct what should you do to make you become a theory
LenKa [72]
D. Collect more evidence and try to convince the other scientist
6 0
4 years ago
A stretched string has a mass per unit length of 5.12 g/cm and a tension of 19.3 N. A sinusoidal wave on this string has an ampl
Sati [7]

Answer:

a. 0.143 mm b. 77.6 rad/m c. 483.18 rad/s  d. +1

Explanation:

a. ym

Since the amplitude is 0.143 mm, ym = amplitude = 0.143 mm

b. k

We know k = wave number = 2π/λ where λ = wavelength.

Also, λ = v/f where v = speed of wave in string = √(T/μ) where T = tension in string = 19.3 N and μ = mass per unit length = 5.12 g/cm = 5.12 ÷ 1000 kg/(1 ÷ 100 m) = 0.512 kg/m and f = frequency = 76.9 Hz.

So, λ = v/f = √(T/μ)/f

substituting the values of the variables into the equation, we have

λ = √(T/μ)/f

= √(19.6 N/0.512 kg/m)/76.9 Hz

= √(38.28 Nkg/m)/76.9 Hz

= 6.187 m/s ÷ 76.9 Hz

= 0.081 m

= 81 mm

So, k = 2π/λ

= 2π/0.081 m

= 77.6 rad/m

c. ω

ω = angular frequency = 2πf where f = frequency of wave = 76.9 Hz

So, ω = 2πf

= 2π × 76.9 Hz

= 483.18 rad/s

d. The correct choice of sign in front of ω?

Since the wave is travelling in the negative x - direction, the sign in front of ω is positive. That is +1.

4 0
3 years ago
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