Answer: 56.44°
Explanation:
<u>Given:</u>
- Let u represent the current speed of the plane, <u>1.2 Mach</u>
<em>Converting to SI Units (m/s):</em>
= (1.2 mach)(340 ms^-1 / 1 Mach)
u = 408 m/s
- Speed of sound in air, v = 340 m/s
<u>Find:</u>
- Angle the wave front of the shock wave relative to the plane's direction of motion, θ
We have, sinθ = speed of sound / speed of object
sinθ = v / u
θ = sin^-1 (v / u)
= sin^-1 (340 / 408)
θ = 56.44°
<span>The California current on the west coast which runs from north to south and the Gulf Stream on the East coast which runs from south to north.</span>
Answer:
The ballon will brust at
<em>Pmax = 518 Torr ≈ 0.687 Atm </em>
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Explanation:
Hello!
To solve this problem we are going to use the ideal gass law
PV = nRT
Where n (number of moles) and R are constants (in the present case)
Therefore, we can relate to thermodynamic states with their respective pressure, volume and temperature.
--- (*)
Our initial state is:
P1 = 754 torr
V1 = 3.1 L
T1 = 294 K
If we consider the final state at which the ballon will explode, then:
P2 = Pmax
V2 = Vmax
T2 = 273 K
We also know that the maximum surface area is: 1257 cm^2
If we consider a spherical ballon, we can obtain the maximum radius:

Rmax = 10.001 cm
Therefore, the max volume will be:

Vmax = 4 190.05 cm^3 = 4.19 L
Now, from (*)

Therefore:
Pmax= P1 * (0.687)
That is:
Pmax = 518 Torr
It would be B
Explanation:
Because if you're not measuring in inches you want to go the next one down other than inches which would be millimeters!(: hope this helps.