Answer:
(a) The velocity of the car before the brakes were applied is 77.46 ft/s
(b) The time required for the car to stop is 7.8 s
Explanation:
Given;
acceleration of the car, a = 10 ft/s²
distance traveled by the car, d = 300 ft
(a) the velocity of the car before the brakes were applied is given;
v² = u² + 2ad
v² = 0 + 2(10 x 300)
v² = 6000
v = √6000
v = 77.46 ft/s
(b) the time required for the car to stop
d = ut + ¹/₂at²
d = 0 + ¹/₂at²
d = ¹/₂at²
t² = 2d / a
t = √ ( 2d / a)
t = √ ( 2 x 300 / 10)
t = 7.8 s
Therefore, the time required for the car to stop is 7.8 s
Answer:
Explanation:
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Answer:
Amplitude: 2cm
Period: 1/12 s
Wavelength: 10 cm
Speed: 120 cm/s
Explanation:
The amplitud is the vertical distance from the resting position to the crest or to the trough, and the vertical distance from a crest to a trough is two times the amplitude. Therefore the amplitud (A) is:
A= 4cm/2= 2cm
The period (T) is:
s
The wavelength is defined as the horizontal distance from a crest to the nearest crest or from a trough to the nearest trough. The distance from a crest to the nearest tough was given. Therefore two times that distance is the distance from a crest to the nearest crest.
The wavelenght (λ) is:
λ=(2)(5)=10cm
The speed (v) in a wave is given by:
v = λf
v=(10)(12)=120 cm/s
For some reasons, no. If the driver looks focused and has experience, then it would be okay. Again, it could be dangerous if you bump into the truck, it would cause damage to you and your passengers.
Mostly, I would agree with 'No'. :)