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zheka24 [161]
3 years ago
14

In liver cells, the inner mitochondrial membranes are about five times the area of the outer mitochondrial membranes. What purpo

se must this serve? A) It allows for an increased rate of glycolysis.
B) It allows for an increased rate of the citric acid cycle.
C) It increases the surface for oxidative phosphorylation.
D) It increases the surface for substrate-level phosphorylation.
Biology
2 answers:
m_a_m_a [10]3 years ago
6 0

Answer:

Option (C).

Explanation:

Oxidative phosphorylation may be defined as the process of the production of ATP molecule by the use of enzyme and transfer of electrons from one complex to the other complex.

The liver cells has five times large surface area of inner mitochondrial membrane than the outer membrane. This increases the surface area of the inner mitochondrial membrane that increase the rate of the oxidative phosphorylation. The complexes of the electron transport chain is located in the inner mitochondrial membrane.

Thus, the correct answer is option (C).

Sauron [17]3 years ago
6 0

Answer:

The correct answer is option C.

Explanation:

The inner membrane of the mitochondria in liver cells is about five times of that the outer membrane as it helps the expanding the surface area of the inner membrane including cristae which is compartment like structure in the inner membrane.

The expand in the surface area in the inner membrane that helps in enhancing its ability to produce ATP than normal. It increases the surface area for oxidative phosphorylation.

Thus, the correct answer is option C.

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Explanation:

As we know cows are dependent on plants so plants are the producers and cow which consume the produced food are known as consumers.

Plant--->Cow---->Lion----->Fungus (food chain)

Plant:- producer

Cow:-primary consumer

Lion:- secondary consumer

Fungus :- decomposers

5 0
2 years ago
E. coli DNA polymerase III is both highly accurate and highly processive. a) Describe how Pol III avoids the incorporation of im
kogti [31]

Answer/Explanation:

DNA polymerase is the enzyme responsible for replicating DNA. It is hugely important that is performs its functions accurately, as if incorrect bases are incorporated this can lead to mutations that disrupt the structure and function of genes. It adds nucleotides in a 5' - 3' direction only.

DNA polymerase III also has high processivity, which means that for every time it binds DNA, it is able to add many bases before it becomes dissociated.

A. DNA polymerase avoids the incorporation of improperly paired nucleotides in two ways:

  • The first way depends on the structure of the enzyme. If the nucleotide that the enzyme is in the process of adding is not complementary to the template, then the nucleotide will not align with the template, and thus it is more inefficient to add. This inefficiency means the nucleotide is more likely to leave the active site before it is added, and DNA polymerase can replace it with the correct nucleotide.
  • It also has proofreading capabilities. This means, when an incorrect base is added, it recognises the error and can fix this. It can do this because it possesses 3'-5' exonuclease activity. That means, it can chop out incorrectly added bases.

B. Ribonucleotides are the nucleotides that are incorporated into a growing RNA molecule. They are different from deoxyribonucleotides because of the differences in the sugar backbone (ribose vs deoxyribose). Their incorporation would disrupt the structure and function of the DNA, leading to problems with transcription and replication.

DNA polymerase avoids incorporating these nucleotides primarily because of the structure of the enzyme. Ribonucleotides cannot fit into the active site of DNA polymerase due to what is called a "steric filter" or "steric gate". This gate/filter function is performed by specific amino acid residues which usually have a bulky side chain and thus block the incorporation of the 2'OH of the ribose sugar (which is lacking in the deoxyribose sugar)

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3 years ago
The clinical findings of a client with diabetes mellitus show decreased glucose tolerance. Which complication is anticipated in
Savatey [412]

Answer:

Frequent yeast infections.

Explanation:

The two hormones insulin and glucagon hormones maintains the blood glucose level in the body. These hormones are released by the alpha cells and beta cells of the pancreas.

The inadequate amount of the insulin secretion can cause the development of Diabetes Mellitus in the individual. The client shows decrease glucose tolerance. This might cause due to the yeast infection in the client's body as the yeast consumes too much sugar.

Thus, the answer is frequent yeast infections.

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4 years ago
What types of things are the energy subsidy used for?
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<h3>Answer: <u><em>Hope this helps</em></u></h3><h3><u><em /></u></h3>

Explanation:

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