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3 years ago

Find the LCM of 5,12,and 15

2 answers:

8 0

60

Because 60 can be divided by all three of them, and it is the lowest one possible, 30 doesn't work because 30 divided by 12 is 2.5, and that isn't a whole number

Andrews [41]3 years ago

8 0

My answer would be 60

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Find the height of a square pyramid with volume 26.97 ft3 and dimensions of base 3 ft by 3 ft. 7 ft 8 ft 9 ft 10 ft

scoundrel [369]

The answer is 3ft because i know im in high schooland u have to find the legth

5 0

3 years ago

Joshua started cycling at 5:15 pm By 8:09 pm, he has covered a distance of 7250 mWhat was Joshua's average speed during that tim

vivado [14]

The average speed of Joshua during that time is 2500 m/h.

Explanation:

It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.

The total time taken by Joshua from 5:15 pm to 8:09 pm is

$2 { h } 54 \text { min }=2 \mathrm{h}+\frac{54}{60} {h}$

Dividing we get,

$2 { h } 54 \text { min }=2 \mathrm{h}+0.9 {h}$

Adding, we have,

$2 { h } 54 \text { min }=2.9 {h}$

Thus, the total time taken by Joshua is $2.9 {h}$

To determine the average speed we use the formula,

$speed=\frac{distance}{time}$

where $distance=7250$ and $time=2.9$

Hence, substituting the values we have,

$speed=\frac{7250}{2.9}$

Dividing, we get,

$speed=2500$

Thus, the average speed of Joshua during that time is 2500 m/h.

5 0

3 years ago

A park is mapped on a coordinate plane, where C1, C2, C3, and C4 represent chairs and SW1, SW2, and SW3 represent swings. How fa

serg [7]

Answer:

Option (B)

Step-by-step explanation:

To calculate the distance between C2 and SW1 we will use the formula of distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ .

d = $\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^2 }$

Coordinates representing positions of C2 and SW1 are (2, 2) and (-6, -7) respectively.

By substituting these coordinates in the formula,

Distance between these points = $\sqrt{(-6-2)^2+(-7-2)^2}$

= $\sqrt{(64)+(81)}$

= $\sqrt{145}$ units

Therefore, Option (B) will be the correct option.

5 0

3 years ago

Read 2 more answers

If A is nonsingular, then (AT )-1 =(A-1) T . (a) Verify this theorem for 2 × 2 matrices

kipiarov [429]

Answer:

Verified

Step-by-step explanation:

Let the 2x2 matrix A be in the form of:

$\left[\begin{array}{cc}a&b\\c&d\end{array}\right]$

Where det(A) = ad - bc # 0 so A is nonsingular:

Then the transposed version of A is

$A^T = \left[\begin{array}{cc}a&c\\b&d\end{array}\right]$

Then the inverted version of transposed A is

$(A^T)^{-1} = \frac{1}{ad - cb} \left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

The inverted version of A is:

$A^{-1} = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-b\\-c&d\end{array}\right]$

The transposed version of inverted A is:

$(A^{-1})^T = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]$

We can see that

$(A^T)^{-1} = (A^{-1})^T$

So this theorem is true for 2 x 2 matrices

3 0

3 years ago

What is 65÷3 ok ease answer

anzhelika [568]

The Answer Is 21.6 repeating

3 0

3 years ago

Read 2 more answers