In a 2.2 m solution with the same volume there would be 11.825 g of a salt
To solve this we use the equation,
M1V1 = M2V2
where M1 is the concentration of the stock
solution, V1 is the volume of the stock solution, M2 is the concentration of
the new solution and V2 is its volume.
1.75 M x V1 = 0.100 M x 2.0 L
V1 = -.11 L
Answer: the answer is think it yourself
Explanation:
I think it is A correct me if i am wrong hope this helps
