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3 years ago

Which of the following is an example of heat transfer through conduction?

Chemistry

2 answers:

Bumek [7]3 years ago

8 0

Answer:

a pan on the stove getting hot

Explanation:

Conduction is type of heat transfer that involves vibration of particles transferring heat to the ones next to them by collisions. So it requires contact between substances.

Hot air rising is convection which is typical of fluids. The sun drying our clothes is radiation of waves from the sun. And microwaves as the name suggestion heats through radiation of waves. A pan on the stoves however relies on the physical contact between the stove and the pan. So particles of the stove vibrate colliding with the pan particles transferring energy

slava [35]3 years ago

7 0

A pan on the stove getting hot, because the pan is conducting the heat from the stove.

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The mass of an atomic number best refers to the number of

adelina 88 [10]

Answer:

Mass number

Explanation:

5 0

3 years ago

Read 2 more answers

I have 2 samples of solid chalk (aka calcium carbonate). Sample A has a total mass of 4.12 g and Sample B has a total mass of 19

IRINA_888 [86]

Answer:

A) Sample B has more calcium carbonate molecules

Explanation:

M = Molar mass of calcium carbonate = 100.0869 g/mol

$N_A$ = Avogadro's number = $6.022\times 10^{23}\ \text{mol}^{-1}$

For the 4.12 g sample

Moles of a substance is given by

$n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{4.12}{100.0869}\\\Rightarrow n=0.0411\ \text{mol}$

Number of molecules is given by

$nN_A=0.0411\times 6.022\times 10^{23}=2.48\times 10^{22}\ \text{molecules}$

For the 19.37 g sample

$n=\dfrac{19.37}{100.0869}\\\Rightarrow n=0.193\ \text{mol}$

Number of molecules is given by

$nN_A=0.193\times 6.022\times 10^{23}=1.16\times 10^{23}\ \text{molecules}$

$1.16\times 10^{23}\ \text{molecules}>2.48\times 10^{22}\ \text{molecules}$

So, sample B has more calcium carbonate molecules.

The ratio of the elements of carbon, oxygen, calcium atoms, ions, has to be same in both the samples otherwise the samples cannot be considered as calcium carbonate. Same is applicable for impurities. If there are impurites then the sample cannot be considered as calcium carbonate.

7 0

3 years ago

(b)

Luda [366]

The maximum mass of anhydrous zinc chloride that could be obtained from the products of the reaction is 8.18 g

<h3>Stoichiometry </h3>

From the question, we are to determine the maximum mass of anhydrous zinc chloride that could be obtained

From the given balanced chemical equation,

ZnO + 2HCl → ZnCl₂ + H₂O

This means 1 mole of ZnO will completely react with 2 moles of HCl to produce 1 mole of ZnCl₂ and 1 mole of H₂O

From the given information

Number of moles of ZnO = 0.0830 mole

Now, we will calculate the number of moles of HCl that is present

Volume of HCl added = 100 cm³ = 0.1 dm³

Concentration of the HCl = 1.20 mol/dm³

Using the formula,

Number of moles = Concentration × Volume

Number of moles of HCl present = 1.20 × 0.1 = 0.120 mole

Since

1 mole of ZnO will completely react with 2 moles of HCl to produce 1 mole of ZnCl₂

Then,

0.06 mole of ZnO will react with the 0.120 mole of HCl to produce 0.06 mole of ZnCl₂

Therefore, maximum number of moles of anhydrous zinc chloride that could be produced is 0.06 mole

Now, for the maximum mass that could be produced

Using the formula,

Mass = Number of moles × Molar mass

Molar mass of ZnCl₂ = 136.286 g/mol

Then,

Mass = 0.06 × 136.286

Mass = 8.17716 g

Mass ≅ 8.18 g

Hence, the maximum mass of anhydrous zinc chloride that could be obtained from the products of the reaction is 8.18 g

Learn more on Stoichiometry here: brainly.com/question/11910892

3 0

2 years ago

Which matter exists in the gaseous state at room temperature?

Tpy6a [65]

Helium i would think so

3 0

3 years ago

Read 2 more answers

QUESTION 1<br> Calculate the number of moles in 45.0 grams of C2H4O2.

yulyashka [42]

Answer:

0.749351061980325 moles (Exact)

0.75 moles (Rounded to the nearest hundredth)

Hope this Helps!

(Sorry if the answer is confusing)

5 0

2 years ago