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vivado [14]
3 years ago
5

Please help I appreciate it

Mathematics
2 answers:
zalisa [80]3 years ago
8 0

Answer:

Step-by-step explanation:

#1 I

#2 D

#3 K

Anni [7]3 years ago
4 0

Answer:

A

Step-by-step explanation:

g(x) got smaller

A - makes it thinner

B & C - move it to the left or right

D- makes it wider

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Draw a visual model to solve 3/8 × 8/11​
dimulka [17.4K]

Answer:

Step-by-step explanation:

(3/8)*(8/11)=(3*8)/(8*11)= 24/88=12/44=6/22=3/11

or you can symplify 8 and get 3/11 right away.

3 0
2 years ago
Adding unlike fractions<br><br> 1/15+38/100
Daniel [21]

Answer:

134/300 or 67/150

Step-by-step explanation:

the LCM of 15 and 100 is 300. 15 *20 is 300 so we multiply both the numerator and denominator of 1/15 by 20 to get 20/300, with 38/100 we multiply by 3 to get 114/300. Now we add 20/300 and 114/300 to get 134/300 which has a common factor of 2 so we can simply it to 67/150

4 0
3 years ago
Your parents decide to build a rectangular pool in your backyard. They determine that the length of the pool should be 15 feet l
damaskus [11]

Width = X

Length = X + 15

Perimeter of a Rectangle = 2W + 2L

2(X) + 2(X + 15)

2X + 2X + 30

4X + 30

Answer = 4X + 30

Hope this helps! :)

4 0
2 years ago
WILL MARK BRANIEST WHO EVER GETS IT RIGHT PLEASE HELP
Lelu [443]

Answer:

1.02227

not sure if im correct

5 0
3 years ago
Read 2 more answers
A certain semiconductor device requires a tunneling probability of T = 10-5 for an electron tunneling through a rectangular barr
Goryan [66]

Answer:

Generally the barrier width is a = 1.9322 *10^{-9} \ m

Step-by-step explanation:

From the question we are told that

     The tunneling probability required is  T  = 1 * 10^{-5}

      The barrier height is  V_o  = 0.4 eV

       The electron energy is  E = 0.08eV

Generally the wave number is mathematically represented as

      k  =  \sqrt{ \frac{2 * m [V_o - E]}{\= h^2} }

Here m is the mass of the electron with the value  m  =  9.11 *10^{-31} \  kg

         h  is is know as h-bar and the value is  \= h = 1.054*10^{-34} \  J \cdot s

So

          k  =  \sqrt{ \frac{2 * 9.11 *10^{-31 } [0.4 - 0.04] * 1.6*10^{-19}}{[1.054*10^{-34}^2]} }

=>      k = 3.073582 *10^{9}  \ m^{-1}

Generally the tunneling probability is mathematically represented as

          T  = 16 * \frac{E}{V_o }  * [1 - \frac{E}{V_o} ] * e^{-2 * k * a}

So

        1.0 *10^{-5} = 16 * \frac{0.04}{0.4 }  * [1 - \frac{0.04}{0.4} ] * e^{-2 * 3.0736 *10^{9} * a}

=>    6.944*10^{-6}= e^{-2 * 3.0736 *10^{9} * a}

Taking natural log of both sides

          ln[6.944*10^{-6}] = -2 * 3.0736 *10^{9} * a}

=>        -11.8776  = -2 * 3.0736 *10^{9} * a}

=>        a = 1.9322 *10^{-9} \ m

       

4 0
2 years ago
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