Answer:
Step-by-step explanation:
(3/8)*(8/11)=(3*8)/(8*11)= 24/88=12/44=6/22=3/11
or you can symplify 8 and get 3/11 right away.
Answer:
134/300 or 67/150
Step-by-step explanation:
the LCM of 15 and 100 is 300. 15 *20 is 300 so we multiply both the numerator and denominator of 1/15 by 20 to get 20/300, with 38/100 we multiply by 3 to get 114/300. Now we add 20/300 and 114/300 to get 134/300 which has a common factor of 2 so we can simply it to 67/150
Width = X
Length = X + 15
Perimeter of a Rectangle = 2W + 2L
2(X) + 2(X + 15)
2X + 2X + 30
4X + 30
Answer = 4X + 30
Hope this helps! :)
Answer:
Generally the barrier width is 
Step-by-step explanation:
From the question we are told that
The tunneling probability required is 
The barrier height is 
The electron energy is 
Generally the wave number is mathematically represented as
![k = \sqrt{ \frac{2 * m [V_o - E]}{\= h^2} }](https://tex.z-dn.net/?f=k%20%20%3D%20%20%5Csqrt%7B%20%5Cfrac%7B2%20%2A%20m%20%5BV_o%20-%20E%5D%7D%7B%5C%3D%20h%5E2%7D%20%7D)
Here m is the mass of the electron with the value 
h is is know as h-bar and the value is 
So
![k = \sqrt{ \frac{2 * 9.11 *10^{-31 } [0.4 - 0.04] * 1.6*10^{-19}}{[1.054*10^{-34}^2]} }](https://tex.z-dn.net/?f=k%20%20%3D%20%20%5Csqrt%7B%20%5Cfrac%7B2%20%2A%209.11%20%2A10%5E%7B-31%20%7D%20%5B0.4%20-%200.04%5D%20%2A%201.6%2A10%5E%7B-19%7D%7D%7B%5B1.054%2A10%5E%7B-34%7D%5E2%5D%7D%20%7D)
=> 
Generally the tunneling probability is mathematically represented as
![T = 16 * \frac{E}{V_o } * [1 - \frac{E}{V_o} ] * e^{-2 * k * a}](https://tex.z-dn.net/?f=T%20%20%3D%2016%20%2A%20%5Cfrac%7BE%7D%7BV_o%20%7D%20%20%2A%20%5B1%20-%20%5Cfrac%7BE%7D%7BV_o%7D%20%5D%20%2A%20e%5E%7B-2%20%2A%20k%20%2A%20a%7D)
So
![1.0 *10^{-5} = 16 * \frac{0.04}{0.4 } * [1 - \frac{0.04}{0.4} ] * e^{-2 * 3.0736 *10^{9} * a}](https://tex.z-dn.net/?f=1.0%20%2A10%5E%7B-5%7D%20%3D%2016%20%2A%20%5Cfrac%7B0.04%7D%7B0.4%20%7D%20%20%2A%20%5B1%20-%20%5Cfrac%7B0.04%7D%7B0.4%7D%20%5D%20%2A%20e%5E%7B-2%20%2A%203.0736%20%2A10%5E%7B9%7D%20%2A%20a%7D)
=> 
Taking natural log of both sides
![ln[6.944*10^{-6}] = -2 * 3.0736 *10^{9} * a}](https://tex.z-dn.net/?f=ln%5B6.944%2A10%5E%7B-6%7D%5D%20%3D%20-2%20%2A%203.0736%20%2A10%5E%7B9%7D%20%2A%20a%7D)
=> 
=> 