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3 years ago

Suppose that P(A)=0.5, P(B)= 0.4 and P(B/A) =0.6. Find each of the following.

Mathematics

1 answer:

Lady_Fox [76]3 years ago

7 0

Part (a)

P(A) = 0.5

P(B) = 0.4

P(B/A) = 0.6

P(A and B) = P(A)*P(B/A)

P(A and B) = 0.5*0.6

P(A and B) = 0.3

<h3>Answer: 0.3</h3>

==========================================

Part (b)

We'll use the result from part (a)

P(A or B) = P(A) + P(B) - P(A and B)

P(A or B) = 0.5 + 0.4 - 0.3

P(A or B) = 0.6

<h3>Answer: 0.6</h3>

===========================================

Part (c)

A and B are not independent since P(B) does not equal P(B/A). The fact that event A happens changes the probability P(B). Recall that P(B/A) means "probability P(B) based on event A already happened". A and B are independent if P(B) = P(B/A).

Events A and B are not mutually exclusive since P(A or B) is not zero.

<h3>Answer: Neither</h3>

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3 years ago

In 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hir

Ede4ka [16]

Answer:

Explained below.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}= p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

(a)

The sample selected is of size <em>n</em> = 450 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

$\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{450}}=0.0204$

So, the sampling distribution of sample proportion is $\hat p\sim N(0.75,0.0204^{2})$ .

(b)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

$P(p-0.04$

$=P(-1.96$

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.95.

(c)

The sample selected is of size <em>n</em> = 200 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

$\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{200}}=0.0306$

So, the sampling distribution of sample proportion is $\hat p\sim N(0.75,0.0306^{2})$ .

(d)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

$P(p-0.04$

$=P(-1.31$

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.81.

(e)

The probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 450 is 0.95.

And the probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 200 is 0.81.

So, there is a gain in precision on increasing the sample size.

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3 years ago

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The table says that the x value represents the number the years since 1985. To find the number of bald eagle pairs in 1998, we need to calculate x:

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Now plug 13 in for x to find y:

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3 years ago

The answer to this question.

LekaFEV [45]

Answer:

.................................

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3 years ago

19. answer this question.

Irina-Kira [14]

<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

➷ final = original x multiplier^n

n is the number of years

Substitute the values in:

final = 3800 x 1.054^3

final = 4449.440763

The closest answer is A

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

5 0

3 years ago

Read 2 more answers