Answer:
The final velocity of the second car is 57 m/s south.
Explanation:
This is an elastic collision between two train cars. In this case, the total kinetic energy between the two bodies will remain the same.
The formula to apply is :
where ;
Given in the question that;
Apply the formula as;
{14650*18}+{3825*11} = {14650 *6} + {3825 * v₂f}
263700+42075=87900 + 3825v₂f
305775 =87900 + 3825v₂f
305775-87900 = 3825v₂f
217875=3825v₂f
217875/3825 =v₂f
56.96 = v₂f
<u>57 m/s = v₂f { nearest whole number}</u>
Answer:
a) 10.0 m/s
b) -4.68 m/s
Explanation:
Given:
y₀ = 0 m
y = 4.00 m
t = 1.50 s
a = -9.8 m/s²
Find: v₀, v
y = y₀ + v₀ t + ½ at²
4.00 = 0 + v₀ (1.50) + ½ (-9.8) (1.50)²
v₀ = 10.0 m/s
v = at + v₀
v = (-9.8) (1.50) + 10.0
v = -4.68 m/s
The answer is B. It is the same..... hope this helps!