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Genrish500 [490]
3 years ago
5

PLEASE HELP

Mathematics
2 answers:
mario62 [17]3 years ago
8 0

Answer:

(2.05x)+6

Step-by-step explanation:

x would be the miles and you multiply that by your fare per mile and add the 6 dollar tip

adell [148]3 years ago
4 0

Answer:

The taxi fare was $2.10 per mile, and she gave the driver a tip of $5. Ann paid a total of $49.10.

49.10 = 2.10(x) + 5

44.10 = 2.10(x)

x = 21 miles

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From the sum of 4a + b + c and 9a - c subtract the sum of 18a - b - c and 14a - 2b - c
sergiy2304 [10]

1:-

\\ \rm\Rrightarrow 4a+b+c+9a-c

\\ \rm\Rrightarrow 4a+9a+b+c-c

\\ \rm\Rrightarrow 13a+b

2:-

\\ \rm\Rrightarrow 18a-b-c-(14a-2b-c)

\\ \rm\Rrightarrow 18a-b-c-14a+2b+c

\\ \rm\Rrightarrow 18a-14a-b+2b-c+c

\\ \rm\Rrightarrow 4a+b

5 0
2 years ago
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I WILL MARK BRAINIEST <br> PLEASE ANSWER QUESTION 26
Oksana_A [137]

Answer: (0,-10) and the transformation should be a reflection

Step-by-step explanation:

5 0
3 years ago
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What are the coordinates of A after reflecting across the line x = 3?
Pachacha [2.7K]

Answer:

It would be (3,2) since it is being reflected over the line it is already on

Step-by-step explanation:

3 0
2 years ago
I understand the switching of positive and negative signs but I don’t understand how to get to the next step which is the answer
Finger [1]
2ab - 3a = a.(2b-3)

now the same thing

let's say n=1

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Understood?

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2 years ago
Planes Q and R are parallel. Lines a and b are shown on planes Q and R, respectively. Planes Q and R are parallel. Plane Q conta
natita [175]

Answer:

They are skew lines.

Step-by-step explanation:

Which statement is true about lines a and b?

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They are perpendicular lines.

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Skew lines are not parallel neither they .They are also not co planar i.e they lie in different planes.

We have two plane Q and R . We have two line a and b on the different planes Q and R. Both planes are parallel but the lines a and b are in different directions. Therefore they are skew lines . They do not intersect and are also not parallel neither co planar.

7 0
3 years ago
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