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Genrish500 [490]
3 years ago
5

PLEASE HELP

Mathematics
2 answers:
mario62 [17]3 years ago
8 0

Answer:

(2.05x)+6

Step-by-step explanation:

x would be the miles and you multiply that by your fare per mile and add the 6 dollar tip

adell [148]3 years ago
4 0

Answer:

The taxi fare was $2.10 per mile, and she gave the driver a tip of $5. Ann paid a total of $49.10.

49.10 = 2.10(x) + 5

44.10 = 2.10(x)

x = 21 miles

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If you bought a tv for $350 and you bought it at a 10% discount off what was the original price
blagie [28]
(not sure if I'm right) Using this Formula Part/Whole = %/100

$350/Original Price = 10%/100
cross multiply 
10w = 35,000
divide by 10 on both sides 
W = $3,500 
(seems real high so I'm not sure)

6 0
3 years ago
Write an equation in standard form using integers <br><br> Y= - x<br> —<br> 5
kykrilka [37]

Answer:

x + y = - 5

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Given

y = - x - 5 ( add x to both sides )

x + y = - 5 ← in standard form

8 0
3 years ago
Factor x^2+5x-50<br> A. (x+25)(x-2)<br> B. (x-5)(x+10)<br> C. (x-10)(x+5)<br> D. (x+2)(x-25)
Drupady [299]
The answer would be B
7 0
3 years ago
A poll asked 1057 American adults if they believe there was a conspiracy in the assassination of President Kennedy, and found th
AVprozaik [17]

Answer:

The 95% confidence interval of the proportion of Americans who believe in the conspiracy is  0.551<  p <  0.610

Step-by-step explanation:

From the question we are told that

   The sample size is  n =1057

   The number that believe there was a conspiracy is  k = 614

Generally the sample proportion is mathematically represented as

      \^ p =  \frac{614}{1057 }

=>   \^ p = 0.5809

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

=>   E = 1.96 * \sqrt{\frac{0.5809 (1- 0.5809)}{1057} }    

=>   E = 0.02975  

Generally 95% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

=>    0.5809 - 0.02975<  p <  0.5809 + 0.02975

=>    0.551<  p <  0.610

4 0
3 years ago
Student records suggest that the population of students spends an average of 6.30 hours per week playing organized sports. The p
Ymorist [56]

Answer:

a) 99.24% chance HLI will find a sample mean between 5.5 and 7.1 hours.

b) 81.64% probability that the sample mean will be between 5.9 and 6.7 hours.

Step-by-step explanation:

To solve this question, it is important to know the Normal probability distribution and the Central Limit Theorem

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

In this problem, we have that:

\mu = 6.3, \sigma = 2.1, n = 49, s = \frac{2.1}{\sqrt{49}} = 0.3

A) What is the chance HLI will find a sample mean between 5.5 and 7.1 hours?

This is the pvalue of Z when X = 7.1 subtracted by the pvalue of Z when X = 5.5.

By the Central Limit Theorem, the formula for Z is:

Z = \frac{X - \mu}{s}

X = 7.1

Z = \frac{7.1 - 6.3}{0.3}

Z = 2.67

Z = 2.67 has a pvalue of 0.9962

X = 5.5

Z = \frac{5.5 - 6.3}{0.3}

Z = -2.67

Z = -2.67 has a pvalue of 0.0038

So there is a 0.9962 - 0.0038 = 0.9924 = 99.24% chance HLI will find a sample mean between 5.5 and 7.1 hours.

B) Calculate the probability that the sample mean will be between 5.9 and 6.7 hours.

This is the pvalue of Z when X = 6.7 subtracted by the pvalue of Z when X = 5.9

X = 6.7

Z = \frac{6.7 - 6.3}{0.3}

Z = 1.33

Z = 1.33 has a pvalue of 0.9082

X = 5.9

Z = \frac{5.9 - 6.3}{0.3}

Z = -1.33

Z = -1.33 has a pvalue of 0.0918.

So there is a 0.9082 - 0.0918 = 0.8164 = 81.64% probability that the sample mean will be between 5.9 and 6.7 hours.

5 0
3 years ago
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