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3 years ago

Construct a line that goes through points and . Label the line g.

Mathematics

1 answer:

guapka [62]3 years ago

5 0

Im confused on the question but just make a line and make points through out it and label the line g

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Hello , I need help please and thank you very important

Gre4nikov [31]

A. 84

Because 14x6=84

7 0

3 years ago

Read 2 more answers

The school production of Our Town' was a big success. For opening night. 434 tickets were sold. Students paid $4.00 each, while

Alex73 [517]

Answer:

286 students attended

148 non students attended

Step-by-step explanation:

Given

$Tickets = 434$

$Students = \$4.00$

$Non-Students = \$6.00$

$Total = \$2032.00$

Solving (a): Number of students

Represent students with S and non students with N

So:

$S + N = 434$ --- (1)

$4S + 6N = 2032$ --- (2)

Make N the subject of formula in (1)

$N = 434 - S$

Substitute 434 - S for N in (2)

$4S +6(434 - S) = 2032$

Open Bracket

$4S + 2604 - 6S = 2032$

Collect Like Terms

$4S - 6S = 2032 - 2604$

$-2S = -572$

Divide through by -2

$S = 286$

<em>Hence; 286 students attended</em>

Solving (b):

Recall that

$N = 434 - S$

$N = 434 - 286$

$N = 148$

<em>148 non students attended</em>

4 0

3 years ago

Find the center and radius of this

ipn [44]

$\text{Hello there! :)}$

Answer:

$\boxed{\text{Center at } (7, -4), \text{ Radius of } 7.}$

$\text{Formula for a circle: } (x - h)^{2} + (y - k)^{2} = r^{2} \text{ Where:}$

$h = \text{ x-coordinate of center}\\\\k = \text{ y-coordinate of center}\\\\r = \text{ radius}\\\\\text{Therefore:}$

$\text{In the equation } (x - 7)^{2} + (y + 4)^{2} = 49:$

$h = 7\\\\k = -4\\\\r = \sqrt[]{49} = 7 \\\\\text{So:}$

$\text{Center at } (7, -4), \text{ Radius of } 7.$

3 0

3 years ago

Read 2 more answers

the slope of line PQ is m= 1/4. find the equation of the line that is parallel to line PQ and that has the y intercept b= -3

nevsk [136]

For this case we have that the generic equation of the line is given by:
$y = mx + b
$
Where,
m: slope of the line
b: intersection with the y axis.
Since the line is parallel to PQ, then the slopes are equal.
We have then:
$m = 1/4.
$
On the other hand we have:
$b = -3
$
Substituting values we have:
$y = (1/4) x - 3$
Answer:
The equation of the line that is parallel to line PQ and that has the and intercept b = -3 is:
$y = (1/4) x - 3$

4 0

3 years ago

The function f is linear. If f(2) = 2 and f(-6)=6 find f(6)

lina2011 [118]

$The\ slope-intercept\ form:y=mx+b\\\\f(2)=2\to for\ x=2\to y=2\\f(-6)=6\to for x=-6\to y=6\\\\put\ in\ equation\ of\ the\ line:\\\\ -\left\{\begin{array}{ccc}2=2m+b\\6=-6m+b\end{array}\right\ \ \ |subtract\ sides\ of\ the\ equations\\----------\\.\ \ \ -4=8m\ \ \ \ \ |divide\ both\ sides\ by\ 8\\.\ \ \ \ \boxed{m=-\frac{1}{2}}\\\\put\ m=-\frac{1}{2}\ to\ equation\ 2=2m+b:\\\\2=2\cdot(-\frac{1}{2})+b\\2=-1+b\ \ \ \ |add\ 1\ to\ both\ sides\\\boxed{b=3}\\\\\boxed{\boxed{y=-\frac{1}{2}x+3}}$

$therefore:f(x)=-\frac{1}{2}x+3\Rightarrow f(6)=-\frac{1}{2}\cdot6+3=-3+3=0\\\\Answer:\boxed{f(6)=0}$

5 0

3 years ago