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Lyrx [107]
3 years ago
5

Construct a line that goes through points and . Label the line g.

Mathematics
1 answer:
guapka [62]3 years ago
5 0
Im confused on the question but just make a line and make points through out it and label the line g
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Area of circle if circumference is 132m
ElenaW [278]

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1386 cm²

Step-by-step explanation:

Here's your answer!

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Help! I really need to pass!
Dmitriy789 [7]

Answer:

\huge{ \boxed{ \bold{ \sf{y =  - 2x + 6}}}}

☥ \tt{Question} :

  • Write the equation of a line in slope - intercept form that has a slope of -2 and passes through the point ( - 1 , 8 ).

☥ \tt{Step  -  \: by \:  -  \: step \: explanation}

☪ \underline{ \underline{ \text{Given : }}}

  • Slope ( m ) = -2
  • Given point = ( - 1 , 8 )

☪ \underline {\underline{ \text{To \: find}}} :

  • Equation of a line in slope - intercept form ( i.e y = mx + c )

Let the point ( -1 , 8 ) be ( x₁ , y₁ )

☪ \underline{ \underline{ \text{Solution}}} :

\underline{ \sf{y - y1 = m(x - x1)}}

plug the known values :

↦ \text{y - 8 =  - 2 \{ x - ( - 1) \} }

↦ \text{y - 8 =  - 2(x + 1)}

Distribute -2 through the parentheses :

↦ \text{y - 8 =  - 2x - 2}

Transpose 8 to right hand side and change it's sign

↦ \text{y =  - 2x - 2 + 8}

↦ \boxed{ \text{y =  - 2x + 6}}

And we're done !

Hope I helped!

♡ Have a wonderful day / night ツ

~TheAnimeGirl ♪

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4 0
3 years ago
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Answer:

s = 33

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99=3s

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3 years ago
Which point on the scatter plot is an outlier?
Colt1911 [192]

Answer:

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Step-by-step explanation:

M(3,3)

P(5,5)

N(5,7)

L(6,2)

Other points are : (1,3), (2,3), (2,4), (3,4), (3,5), (4,5), (4,6), (5,6)

Now, To find the outliers on the scatter plot we plot all the given points on the graph.

The resultant graph is attached below :

An outlier is a value in a data set that is very different from the other values. That is, outliers are values which are usually far from the middle.

As we can see the graph the point L(6,2) is the most unusual or the farthest point on the scatter plot as compared with all the other points on the scatter plot.

Hence, The outlier on the the scatter plot is point L(6,2).

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