Answer:
The correct option is
d) (179.20, 212.716)
Step-by-step explanation:
We have out of a random sample of 1000, 345 carried more than a bag
Therefore in the question our X = 345 passengers carry more than a piece of luggage
n = 1000
Therefore the probability of a passenger carrying more than one luggage = 345/1000 = 0.345
The confidence interval estimator of p is given by
where p' = 0.345 = probability of desired outcome
n = 1000 = Population size
z at 95 % = Confidence interval estimate, the value is sought from the distribution table as z value is 1.96 at 95 % confidence level
We have
which gives
0.3745 or 0.3155
Which gives the range of confidential interval estimate as
212.695 to 179.224 which is equivalent to
d) (179.20, 212.716).
Area= length * width
A= 2/5 long * 1/3 wide
A= (2 * 1) / (5 * 3)
A= 2/15
2/15 is the area & simplest form
Hope this helps! :)
Let us assume that even F represents fidelity and event S represents selectivity.
We have been given the probabilities:
P(S) = 0.72, P(F) = 0.59 and 
We need to find the conditional probability that a system with high fidelity will also have high selectivity. We know the conditional probability formula:

Upon substituting the given values, we get:


Answer:
25.2
Step-by-step explanation:
4 1/5 = 4.2
4.2 x 6 = 25.2
5 part marker and 1 part pencil 5+1=6 54/6=9 9 pencils 9 times 5 45 markers