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nydimaria [60]
3 years ago
12

The power rating of a 400-Ω resistor is 0.800 W.(a) What is the maximum voltage that can be applied across this resistor without

damaging it? Use three significant figures in your answer.
Physics
1 answer:
yanalaym [24]3 years ago
4 0

Answer:

V=17.9\ Volt

Explanation:

<u>Joule's Law in Electricity</u>

The Joule's law allows us to calculate the power dissipated in a resistor of resistance R through which goes a current I.

P=I^2R

The relation between the voltage and the current is given by Ohm's law:

V=RI

Solving for I and replacing int the first equation

\displaystyle P=\frac{V^2}{R}

Solving for V

V=\sqrt{PR}

V=\sqrt{0.8\cdot 400}=17.9

\boxed{V=17.9\ Volt}

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