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vodomira [7]
3 years ago
10

How much work would a child do while puling a 12-kg wagon a distance of 3m with a 22 N force directed 30 degrees with respect to

the horizontal? (A) 82J (B) 52J (C) 109J (D) 95J
Physics
1 answer:
Alika [10]3 years ago
6 0

Answer:

The work done will be 57.15 J

Explanation:

Given that,

Mass = 12 kg

Distance = 3 m

Force = 22 N

Angle = 30°

We need to calculate the work done  

The work done is defined as,

W = Fd\cos\theta

Where, F = force

d = displacement

Put the value into the formula

W=22\times3\times\cos30^{\circ}

W=22\times3\times\dfrac{\sqrt{3}}{2}

W = 57.15\ J

Hence, The work done will be 57.15 J

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Answer:

the third law

Explanation:

could u vote me brainliest plz? thx :)

4 0
3 years ago
an object of mass 8 kg is whriled round in a vertical circle of radius 2m with a constant speed of 6m/s .Then the maximum and mi
algol13

Answer:

Maximum Tension=224N

Minimum tension= 64N

Explanation:

Given

mass =8 kg

constant speed = 6m/s .

g=10m/s^2

Maximum Tension= [(mv^2/ r) + (mg)]

Minimum tension= [(mv^2/ r) - (mg)]

Then substitute the values,

Maximum Tension= [8 × 6^2)/2 +(8×9.8)] = 224N

Minimum tension= [8 × 6^2)/2 -(8×9.8)]

=64N

Hence, Minimum tension and maximum Tension are =64N and 2224N respectively

5 0
2 years ago
Playing a certain musical note on a trumpet
Virty [35]

Answer:

(1) Resonance

Explanation:

Resonance is the process whereby a system is set into vibration due to the vibration of a nearby system with larger amplitude. The frequency at which this vibration takes place is called the resonant frequency.

It is a phenomenon of amplification that occurs when the frequency of a periodically applied force is in harmonic proportion to the natural frequency of the system on which it acts.

7 0
3 years ago
The relationship between the Period (T) caused by the oscillation of the mass on the end of a hanging spring and the mass (m) is
blondinia [14]

Answer:

T= 2p√m/k

Explanation:

This is because the period of oscillation of the mass of spring system is directly proportional to the square root of the mass and it is inversely proportional to the square root of the spring constant.

The period of a mass on a spring is given by the equation

T=2π√m/k.

Where T is the period,

M is mass

K is spring constant.

An increase in mass in a spring increases the period of oscillation and decrease in mass decrease period of oscillation.

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7 0
3 years ago
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