Answer:
(3,-4) or x=3 and y= -4
Step-by-step explanation:
I'm going to solve this by substitution
We first need to get a variable by itself in one of the two equations (it doesn't matter which variable and the equation you do the work on doesn't matter either)
I'm going to solve for y in the second equation
-4x-4y=4
add 4y and subtract 4 from both sides to get
-4x-4=4y
Divide by 4 to get
-x-1=y
We can plug this value in for y into the first equation and get
4x+5(-x-1)= -8
Solve for x
4x-5x-5= -8
-x-5= -8
-x= -3
x=3
We can plug this value into one of the first two equations and solve for y
4(3)+5y= -8
12+5y= -8
5y= -20
y= -4
Therefore the solution is (3,-4) or x=3 and y= -4
Answer:
Clockwise
Step-by-step explanation:
Sorry I answered late
Answer:
Step-by-step explanation:
Answer: C
Step-by-step explanation:
Simplify to 4x^2 + 12x + 5 = 0 so that all the terms are on one side.
Do a part of the quadratic formula to see.
You only need to do the 
part. If it is negative, that means there are irrational solutions. If it is positive, it has two solutions. If it is 0, it has 1 solution.
It is positive so it has two solutions.
