1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
leonid [27]
3 years ago
6

The energy released by the exploding gunpowder in a cannon propels the cannonball forward. Simultaneously, the cannon recoils. T

he mass of the cannonball is less than that of the cannon. Which has the greater kinetic energy, the launched cannonball or the recoiled cannon? Assume that momentum conservation applies.
Physics
1 answer:
Lelechka [254]3 years ago
4 0

Answer:

the launched cannonball

Explanation:

You might be interested in
When an alkali metal is involved in a chemical reaction with a nonmetal, what charge will its atoms most likely form? 1- 2- 2+ 1
seraphim [82]

Answer:

+1 ion

Explanation:

Alkali metals are metals that are found in Group I of the periodic table. Their electronic configuration is such that their valence shell in grounds state is always holding only one electron which they always lose when reacting with non-metals. A loss in an electron makes the atom electrically imbalanced and hence becoming a +1 ion.

7 0
3 years ago
What is the force of gravitational attraction between an object with a mass of 100 kg and another object that has a mass of 300
Leokris [45]

Answer:

5 x 10⁻⁷N

Explanation:

Given parameters:

Mass of object 1  = 100kg

Mass of object 2 = 300kg

Distance  = 2m

Unknown:

Force of gravitational attraction between the objects  = ?

Solution:

Newton's law of universal gravitation states that the gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

From Newton's law of universal gravitation we derive an expression:

       Fg  =  \frac{Gm_{1} m_{2}  }{r^{2} }

G is the universal gravitation constant = 6.67 x 10⁻¹¹

m is the mass

r is the distance between the bodies

Now insert the parameters and solve;

    Fg  = 6.67 x 10⁻¹¹ x \frac{100 x 300}{2^{2} }    = 5 x 10⁻⁷N

7 0
3 years ago
An insect 1.1 mm tall is placed 1.0 mm beyond the focal point of the objective lens of a compound microscope. The objective lens
Pavlova-9 [17]

Answer:

Explanation:

For image formation in objective lens

object distance u = 14 +1 = 15 mm

focal length f = 14 mm .

image distance v = ?

lens formula

\frac{1}{v} -\frac{1}{u} =\frac{1}{f}

Putting the values

\frac{1}{v} +\frac{1}{15} =\frac{1}{14}

v = 210 mm .

B )

magnification = v / u

= 210 / 15

= 14

size of image = 14 x 1.1 mm

= 15.4 mm

= 15 mm approx

C )

For final image to be at infinity , image produced by objective lens must fall at the focal point of eye piece . so objective lens's distance from the image formed by objective must be equal to focal length of eye piece that is 21 mm .

21 mm is the answer .

D )

overall magnification =

\frac{210}{15} \times \frac{D}{f_e}

D = 25 cm , f_e = focal length of eye piece

= 14 x 250 / 21

= 166.67

= 170 ( in two significant figures )

7 0
3 years ago
Boyle’s Law states that when a sample of gas is compressed at a constant temperature, the pressure P of the gas is inversely pro
jolli1 [7]

Answer:

a)V=\dfrac{5.3}{P}

b)ML^{-4}T^{-2}.

Explanation:

Given that

Boyle's law

P V = Constant ,at constant temperature

a)

Given that

P_1=50KPa

V_1=0.106m^3

We know that for PV=C

P_1V_1=P_2V_2=PV

Now by putting the values

PV= 50 x 0.106

V=\dfrac{5.3}{P}

Where P is in KPa and V is in m^3

b)

PV= C

Take ln both sides

So \ln(PV)=\ln C

lnP + lnV =lnC               ( C is constant)

By differentiating

\dfrac{dP}{P}+\dfrac{dV}{V}=0

So

\dfrac{dP}{dV}=-\dfrac{P}{V}

When P= 50 KPa

\dfrac{dP}{dV}=-\dfrac{50}{V}\ \dfrac{KPa}{m^3}

It indicates the slope of PV=C curve.

It unit is \dfrac{Pa}{m^3}.

Or we can say that ML^{-4}T^{-2}.

5 0
3 years ago
Read 2 more answers
A police car in a high-speed chase is traveling north on a two-lane highway at 35.0 m/s. In the southbound lane of the same high
Sati [7]

Answer:

53 m/s

Explanation:

Since we take the positive x-direction to be toward the north, an SUV travelling to the south would have a negative velocity, -18m/s, relative to Earth. Velocity of Earth relative to the SUV would be 18m/s. And velocity of police car relative to Earth would be positive, 35 m/s.

Velocity of police relative to SUV would equal to velocity of police car relative to Earth plus velocity of Earth relative to SUV

= 35 + 18 = 53 m/s

3 0
3 years ago
Other questions:
  • Which celestial body is named after a Roman god or goddess? Ceres Haumea Titania Ariel
    5·1 answer
  • 8. The amount of water pressure you experience while swimm
    14·1 answer
  • You are working at a company that manufactures electrical wire. Gold is the most ductile of all metals: it can be stretched into
    10·1 answer
  • Which specialized science would you consult before cultivating your new field or farm for better and profitable yields? A. biote
    8·2 answers
  • How many kilograms of water can completely fill a
    6·1 answer
  • Two circles are drawn in a 12-inch by 14-inch rectangle. Each circle has a diameter of 6 inches. If the circles do not extend be
    10·1 answer
  • A football coach walks 24 meters eastward, then 12 meters
    12·1 answer
  • A gas engine that operates on a Brayton cycle has an efficiency of 0.25. On a cold day, the temperature of the air drawn into th
    15·1 answer
  • What is displacement? A. the rate of change of distance of an object over time B. the specific speed and direction in which an o
    10·1 answer
  • Please answer this soon
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!