Answer:
0.75 NC⁻¹
Explanation:
Electric field intensity ( or strength of the electric field ) is the force per a 1 C charge,
So, Force (F) = Electric field intensity(E) × Charge (q)
F = E×q ⇒ q = F/E
= 4.5×10⁻⁴/6×10⁻⁴ = 0.75 NC⁻¹
According to cool om's law electric fields are generated due to charges. When charges are same there is a repulsive force acted on both charges. When charges are opposite there is a attraction force acted on both charges.
According to cool om's law,
F =G×q1×q2 / r²
F = force exerted of two charges
q1 , q2 = charges
r = distance between two charges
And also Electric field intensity is a vector which has a magnitude and direction both. Direction is depending on a charge and the sign of the charge
Explanation:
1. Mass of the proton, 
Wavelength, 
We need to find the potential difference. The relationship between potential difference and wavelength is given by :



V = 45.83 volts
2. Mass of the electron, 
Wavelength, 
We need to find the potential difference. The relationship between potential difference and wavelength is given by :




V = 84109.27 volt
Hence, this is the required solution.
Explanation:
Below is an attachment containing the solution.