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4 years ago

If medain of 10, 20, x+5,x+10,50,60 is 35 then find x

Mathematics

1 answer:

SVETLANKA909090 [29]4 years ago

7 0

Answer:

X = 27

Step-by-step explanation:

10, 20, 32, 37, 50, 60

First things first, take off 10, 20, 50, and 60.

Now, you remain with 32 and 37. Now from here it is simple.

Average of 32 and 37 = 34.83

Round 34.83 to 35

32 averaging 37 (Rounding Terms) ≈ 35

So X is 27

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2 years ago

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There are two triangles, a big triangle and a small triangle that is inside the big triangle. Because the base of the triangles are parallel to each other( indicated by the arrow), and the small triangle is perfectly inside the bigger triangle, the sides of the triangles are proportional.

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3 years ago

How do I find an equation that has an infinite solution

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3 years ago

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A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t

MakcuM [25]

Answer:

$165$ .

Step-by-step explanation:

Since repetition isn't allowed, there would be $11$ choices for the first donut, $(11 - 1) = 10$ choices for the second donut, and $(11 - 2) = 9$ choices for the third donut. If the order in which donuts are placed in the bag matters, there would be $11 \times 10 \times 9$ unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type $3 \times 2 \times 1 = 6$ times.

For example, if a bag includes donut of type $x$ , $y$ , and $z$ , the count $11 \times 10 \times 9$ would include the following $3 \times 2 \times 1$ arrangements:

$xyz$ .
$xzy$ .
$yxz$ .
$yzx$ .
$zxy$ .
$zyx$ .

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count $11 \times 10 \times 9$ by $3 \times 2 \times 1 = 6$ to find the actual number of donut combinations:

$\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

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2 years ago

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Makovka662 [10]

Answer:

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