1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Harrizon [31]
3 years ago
11

If brownies are baked in a pan measuring 13 inches long by 9 inches

Mathematics
1 answer:
nataly862011 [7]3 years ago
3 0

Answer:

The brownies will be a little thicker in a 9 x 13” pan. 8 x 8= 64 square inches, doubled that's 128. 9 x 13= 117

Step-by-step explanation:

You might be interested in
In a randomly selected sample of 1169 men ages 35–44, the mean total cholesterol level was 210 milligrams per deciliter with a s
Aneli [31]

Answer:

The highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10% is 160.59 milligrams per deciliter.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 210, \sigma = 38.6

Find the highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10%.

This is the 10th percentile, which is X when Z has a pvalue of 0.1. So X when Z = -1.28.

Z = \frac{X - \mu}{\sigma}

-1.28 = \frac{X - 210}{38.6}

X - 210 = -1.28*38.6

X = 160.59

The highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10% is 160.59 milligrams per deciliter.

5 0
3 years ago
ΔABC is similar to ΔDEF. The length of segment AC is 12 cm. The length of segment BC is 18 cm. The length of segment DF is 10 cm
SCORPION-xisa [38]

Answer:

It's 15

i took the test

Step-by-step explanation:

5 0
3 years ago
Pls help me i dont know how to do it
denis-greek [22]
I would start by multiplying both sides of the inequality by 4 to eliminate the fraction

y + 8 >/= 12
Then subtract 8 from both sides
y >/= 4

Because it is greater than OR equal to, when you graph, you use a solid circle. Greater than means the arrow goes to the right on the line.

So, solid circle on the line on 4, arrow pointing to the right. (Third option from the right)
3 0
3 years ago
How many triangles can be constructed with sides measuring 6 cm, 2 cm, and 7 cm?
Katen [24]
One i think i’m not sure tho
8 0
3 years ago
Read 2 more answers
A circle has a radius of 18.2 cm. Find the
pishuonlain [190]

Answer:

54.6cm

Step-by-step explanation:

Arc length = radius * central angle

= 18.2*3

=54.6

6 0
3 years ago
Other questions:
  • Answers for adding and subtracting polynomials
    6·1 answer
  • 5. Two angles are supplements if their sum is 180 degrees. The measurement of one angle is five more than six times its suppleme
    6·1 answer
  • can someone please help me I have a ton of math work and I struggle with it so hard. I'll give extra points
    6·2 answers
  • Please help ASAP on number 29.
    5·1 answer
  • Which is the mode of this data set? 55, 78, 43, 39, 78, 61, 75, 50, 43, 78
    12·1 answer
  • Spending a day observing a professional in his or her work
    8·2 answers
  • A bike path crosses a road as shown. Solve for each indicated angle measure or variable.
    9·1 answer
  • Find the distance between (-8, -1) and (0, 5). Give your answer in simplest radical form.
    12·1 answer
  • What is the length of the arc shown in​ red?
    11·1 answer
  • Get it right I need this bro
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!