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Arturiano [62]
2 years ago
11

Expand the logarithm. ln((-3e^5)/(x^3))

Mathematics
1 answer:
Valentin [98]2 years ago
7 0

Answer:

ln(3) + 5 - 3ln(x) or 6.0986 - 3ln(x)

Step-by-step explanation:

ln(\frac{3e^{5} }{x^3} )

ln(\frac{3e^{5} }{x^3} ) = ln(3e^5)-ln(x^3), since ln(x/y) = ln(x)-ln(y)

ln(3e^5) = ln(3) + ln(e^5), since ln(xy) = ln(x) + ln(y)

ln(\frac{3e^{5} }{x^3} ) = ln(3) + ln(e^5)-ln(x^3)

ln(\frac{3e^{5} }{x^3} ) = ln(3) + 5ln(e) -3ln(x), since ln(x^y) = yln(x)

ln(\frac{3e^{5} }{x^3} ) = ln(3) + 5 -3ln(x) , since ln(e)=1

if needed further simplification,

ln(3) = 1.0986

ln(e) = 1

ln(\frac{3e^{5} }{x^3} ) = 6.0986 - 3ln(x)

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