if the diameter of a circle is 15, its radius is half that or 7.5.
![\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=7.5 \end{cases} A=\pi (7.5)^2\implies A=56.25\pi \implies \stackrel{\pi =3.14}{A=176.625}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D7.5%20%5Cend%7Bcases%7D%20A%3D%5Cpi%20%287.5%29%5E2%5Cimplies%20A%3D56.25%5Cpi%20%5Cimplies%20%5Cstackrel%7B%5Cpi%20%3D3.14%7D%7BA%3D176.625%7D%20)
2(15+N)
replace a number by N
replace the sum of 15 and N by (15+N)
and lastly, replace twice by 2
So your answer is 2(15+N)
Answer:

Step-by-step explanation:
we know that
<u><em>Combinations</em></u> are a way to calculate the total outcomes of an event where order of the outcomes does not matter.
To calculate combinations, we will use the formula

where
n represents the total number of items
r represents the number of items being chosen at a time.
In this problem

substitute

simplify




It is not an equilateral triangle. To prove this, you must solve for x. I found x by setting 2x+5.2 = 3x+1.2 to get x=4. Then I plugged 4 into equation to see if they were equal. 2(4)+5.2= 13.2 and 3(4)+1.3=13.2 but 2(4)+6.2=14.2. This allows us to conclude that the triangle is not equilateral because all of the sides are NOT congruent. Hope that helped:))
the answer to that question is 31.80