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3 years ago

A line passes through the point (-4, -8) and has a slope of 5/2 write an equation in slope intercept form for this line

Mathematics

1 answer:

Tju [1.3M]3 years ago

4 0

Answer:

y = 5x/2 + 2

Step-by-step explanation:

We know the equation for slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. Since we have the coordinates of one point on this line and the slope, we can substitute that in and find b first:

y = mx + b

-8 = 5/2(-4) + b

-8 = -10 + b

b = 2

So we can use the slope and this y intercept we found to plug back into the equation:

y = mx + b

y = 5x/2 + 2

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Answer:

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Step-by-step explanation:

$x\frac{\mathrm{dy} }{\mathrm{d} x}=x^{3}+3y\\\\Rearranging \\\\x\frac{\mathrm{dy} }{\mathrm{d} x}-3y=x^{3}\\\\\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{3y}{x}=x^{2}$

This is a linear diffrential equation of type

$\frac{\mathrm{d} y}{\mathrm{d} x}+p(x)y=q(x)$ ..................(i)

here $p(x)=\frac{-2}{x}$

$q(x)=x^{2}$

The solution of equation i is given by

$y\times e^{\int p(x)dx}=\int e^{\int p(x)dx}\times q(x)dx$

we have $e^{\int p(x)dx}=e^{\int \frac{-2}{x}dx}\\\\e^{\int \frac{-2}{x}dx}=e^{-2ln(x)}\\\\=e^{ln(x^{-2})}\\\\=\frac{1}{x^{2} } \\\\\because e^{ln(f(x))}=f(x)]\\\\Thus\\\\e^{\int p(x)dx}=\frac{1}{x^{2}}$