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Vika [28.1K]
3 years ago
11

WILL GIVE BRAINLIEST!!! HELP ASAP!!!

Biology
1 answer:
Sauron [17]3 years ago
5 0

Answer:

The last one

Explanation:

They are both found in the middle and everything else is false

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Which is NOT an example of a renewable energy source?
kati45 [8]

Answer:

coal

Explanation:

wind and water never end so they're renewable and the sun like ofc also never ends

but you can run out of coal

3 0
2 years ago
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Explain how living things, such as people and trees, are different from nonliving things, such as rocks and the tent.
Alexus [3.1K]
LIVING THINGS BREATHE NON LIVING THINGS DOSENT
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At which stage is glucose broken into smaller molecules? A. before cellular respiration begins B. during the first stage of cell
Vesnalui [34]

b. the first stage because it could never be in the secound stage

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Identify the structures of the heart.
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7 0
3 years ago
Suppose a species of bird called the red-crested warbler has a plumage length that is controlled by a single gene. The Plm allel
AleksAgata [21]

We are going to have different allele frequencies for the two populations

North American:

72 birds total => 144 alleles

72 - 55 birds = 17 short plume birds.

q^2 = (2*17) / 114 = 0.236

Freq(short plume allele) = q = 0.486

Freq(long plume allele) = p = 1 - q = 0.514

From this North American population we get

0.486 * 114 = 55 long plume alleles

0.514 * 114 = 59 short plume alleles

South American:

252 birds total => 504 alleles

252 - 75 birds = 177 short plume birds.

q^2 = (2*177) / 504 = 0.702

Freq(short plume allele) = q = 0.838

Freq(long plume allele) = p = 1 - q = 0.162

From this South American population we get

0.162 * 504 = 82 long plume alleles

0.838 * 504 = 422 short plume alleles

Blended population has

55 + 82 = 137 long plume alleles

59 + 422 = 481 short plume alleles

137 + 481 = 618 total alleles

p = 137/618 = 0.222

q = 481/618 = 0.778

The new population has the p and q from the blended population. The new population has 1000 individuals. The portion of long plumed will be homozygote long plumage + heterozygote, which is p^2 + 2pq, and you multiply that by the population size 1000 to get the final answer.

population size * (p^2 + 2pq) = 1000 * (0.222^2 + 2*0.222*0.778) = 395 birds (answer)

6 0
3 years ago
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