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max2010maxim [7]
3 years ago
11

Can someone plz help me solved this problem I need help plz help me! Will mark you as brainiest!

Mathematics
1 answer:
stira [4]3 years ago
4 0

Answer:

the second question is 350 I think

Step-by-step explanation:

You might be interested in
Are all triangles prisms or pyramids
Umnica [9.8K]

Answer:

No not all of them.

Step-by-step explanation:

Triangles can be 2d meaning like a flat triangle.

8 0
3 years ago
You are going to design an advertisement for a new polynomial identity that you are going to invent. Your goal for this activity
Zigmanuir [339]

Answer:(ax+b) (x+a)

Use FOIL on second term

Assignment details:

It's time to show off your creativity and marketing skills!

You are going to design an advertisement for a new polynomial identity that you are going to invent. Your goal for this activity is to demonstrate the proof of your polynomial identity through an algebraic proof and a numerical proof in an engaging way! Make it so the whole world wants to purchase your polynomial identity and can't imagine living without it!

You may do this by making a flier, a newspaper or magazine advertisement, making an infomercial video or audio recording, or designing a visual presentation for investors through a flowchart or PowerPoint.

You must:

• Label and display your new polynomial identity

• Prove that it is true through an algebraic proof, identifying each step

• Demonstrate that your polynomial identity works on numerical relationships

WARNING! No identities used in the lesson may be submitted. Create your own. See what happens when different binomials or trinomials are combined. Below is a list of some sample factors you may use to help develop your own identity.

• (x – y)

• (x + y)

• (y + x)

• (y – x)

• (x + a)

• (y + b)

• (x2 + 2xy + y2)

• (x2 – 2xy + y2)

• (ax + b)

• (cy + d)

The numerical proof is correct! This identity had been proven right in front of your eyes

Algebraic Proof

Amber Carter

Polynomial Identities

So, you want even more proof? Well then lets just substitute in values for a, b, and x. Lets make a=2, b=4, and x=6.

(ax+b) (x+a) = ax^2 +a^2x +bx +ab

(ax+b) (x+a)

+bx +ab

(ax+b) (x+a)=ax^2 +a^2x +bx +ab

This identity is effective and easy to use!

The New Identity

To solve this you have to use the distributive property, more specifically FOIL

Use FOIL on first term

ax^2+a^2x+bx+ab

((2*6)+4) (6+2) = (2^2*6) +(4^2*6) +(2*4)

128 = 128

(16) (8) = (24)+(96)+(8)

Module 4.08

Numerical Proof

I hope this was adequate proof to convince you to love my new polynomial proof!

ax^2+a^2x

The following is an advertisement for the newest polynomial identity. If you like the way your life is now and do not wish to add this new identity to your knowledge, then please do not go any further. This identity is not for those who are non-accepting of new and improved ideas.

Step-by-step explanation:

3 0
3 years ago
On a coordinate plane, point A is located at (7, 4), and point B is located at (-8, 4). What is the distance between the two poi
stiv31 [10]

Answer:

Step-by-step explanation:

Distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\\\ =\sqrt{(-8-7)^{2}+(4-4)^{2}}\\\\ =\sqrt{(-15)^{2}+0}\\\\=\sqrt{225} \\\\=15

5 0
4 years ago
You plan to conduct a survey to find what proportion of the workforce has two or more jobs. You decide on the 95% confidence lev
Vikentia [17]

Answer:

865

Step-by-step explanation:

We have that in 95% confidence level the value of z has a value of 1.96. This can be confirmed in the attached image of the normal distribution.

Now we have the following formula:

n = [z / E] ^ 2 * (p * q)

where n is the sample size, which is what we want to calculate, "E" is the error that is 2% or 0.02. "p" is the probability they give us, 5 out of 50, is the same as 1 out of 10, that is 0.1. "q" is the complement of p, that is, 1 - 0.1 = 0.9, that is, the value of q is 0.9.

Replacing these values we are left with:

n = [1.96 / 0.02] ^ 2 * [(0.1) * (0.9)]

n = 864.36

865 by rounding to the largest number.

3 0
4 years ago
63 1/4 - 2 1/5 show your work please
Tanzania [10]

Answer:

\sf 61\frac{1}{20}

Step-by-step explanation:

Given expression:

\sf 63 \frac{1}{4}-2 \frac{1}{5}

<u>Partition</u> the mixed numbers into <u>fractions</u> and <u>whole numbers</u>, and then subtract them separately.

<u>Subtract</u> the whole numbers:

\implies \sf 63-2=61

<u>Subtract</u> the fractions by changing both fractions into equivalent fractions so both fractions have the <u>same denominator</u>:

\implies \sf \dfrac{1}{4}-\dfrac{1}{5}

\implies \sf \dfrac{1 \times 5}{4 \times 5}-\dfrac{1 \times 4}{5 \times 4}

\implies \sf \dfrac{5}{20}-\dfrac{4}{20}

<u>Subtract</u> the numerator:

\implies \sf \dfrac{5}{20}-\dfrac{4}{20}=\dfrac{1}{20}

Put the two answers from the whole numbers and fractions back together:

\implies \sf 61+\dfrac{1}{20}=61\frac{1}{20}

Therefore:

\implies \sf 63 \frac{1}{4}-2 \frac{1}{5}=61\frac{1}{20}

3 0
2 years ago
Read 2 more answers
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