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Nikolay [14]
3 years ago
12

You plan to conduct a survey to find what proportion of the workforce has two or more jobs. You decide on the 95% confidence lev

el and a margin of error of 2%. A pilot survey reveals that 5 of the 50 sampled hold two or more jobs. How many in the workforce should be interviewed to meet your requirements

Mathematics
1 answer:
Vikentia [17]3 years ago
3 0

Answer:

865

Step-by-step explanation:

We have that in 95% confidence level the value of z has a value of 1.96. This can be confirmed in the attached image of the normal distribution.

Now we have the following formula:

n = [z / E] ^ 2 * (p * q)

where n is the sample size, which is what we want to calculate, "E" is the error that is 2% or 0.02. "p" is the probability they give us, 5 out of 50, is the same as 1 out of 10, that is 0.1. "q" is the complement of p, that is, 1 - 0.1 = 0.9, that is, the value of q is 0.9.

Replacing these values we are left with:

n = [1.96 / 0.02] ^ 2 * [(0.1) * (0.9)]

n = 864.36

865 by rounding to the largest number.

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Help asap pls
Svet_ta [14]

Answer:

Eating dinner and eating dessert are dependent events because

P(dinner) . P(dessert) = 0.9 × 0.6 = 0.54 which is not equal to

P(dinner and desert) = 0.5 ⇒ answer A

Step-by-step explanation:

* Lets study the meaning independent and dependent probability  

- Two events are independent if the result of the second event is not

  affected by the result of the first event

- If A and B are independent events, the probability of both events  

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- P (A and B) = P(A) · P(B)

* Lets solve the question  

∵ There is a 90% chance that a person eats dinner

∴ P(eating dinner) = 90/100 = 0.9

∵ There is a 60% chance a person eats dessert

∴ P(eating dessert) = 60/100 = 0.6

- If eating dinner and dating dessert are independent events, then

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 both events

∵ P(eating dinner and dessert) = P(eating dinner) . P(eating dessert)

∴ P(eating dinner and dessert) = 0.9 × 0.6 = 0.54

∵ There is a 50% chance the person will eat dinner and dessert

∴ P(eating dinner and dessert) = 50/100 = 0.5

∵ P(eating dinner and dessert) ≠ P(eating dinner) . P(eating dessert)

∴ Eating dinner and eating dessert are dependent events because

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  P(dinner and desert) = 0.5

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2 years ago
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Answer:

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24+1 68/100=25 68/100

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