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mojhsa [17]
3 years ago
14

What fraction is equivalent to -(7/8 A: -(7/-8) B: -7/8 C: -(-7/8) D: -7/-8

Mathematics
1 answer:
lianna [129]3 years ago
7 0

Answer:

-(7/8) is equivalent to -7/8

B) -7/8 is correct option

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The table below shows all of the possible outcomes for rolling two six-sided number cubes. A table with 36 possible outcomes. Th
barxatty [35]

The image is missing, we have attached the image.

Answer:

The of getting an even number in first and an odd number second is \frac{1}{4}\ or\ 0.25.

Step-by-step explanation:

Given,

Total number of outcomes = 36

We have to find the probability of rolling an even number first and an odd number second.

Solution,

Firstly we will find out the possible outcomes;

(2,1),\ (2,3),\ (2,5),\  (4,1),\ (4,3),\ (4,5),\ (6,1),\ (6,3),\ (6,5),

So the total number of outcomes = 9

Now according to the formula of probability, which is;

P(E)=\frac{\textrm{total number of possible outcomes}}{\textrm{total number of  outcomes}}

Now on putting the values, we get;

P(of getting an even number in first and an odd number second)=\frac{9}{36}=\frac{1}{4}=0.25

Hence The of getting an even number in first and an odd number second is \frac{1}{4}\ or\ 0.25.

5 0
3 years ago
Read 2 more answers
Discrete Mathematics I
faust18 [17]

ANSWER



The general solution is 86+280n, where n is an  integer



<u>EXPLANATION</u>



In order  to solve the linear congruence;



33x \equiv 38(mod\:280)



We need to determine the inverse of 33 (which is a Bézout coefficient for 33).



To do that we must first use  the Euclidean Algorithm to verify the existence of the inverse by showing that;



gcd(33,\:280)=1



Now, here we go;



280=8\times33+16



33=2\times 16+1



16=2\times 8+0



The greatest common divisor is the last remainder before the remainder of zero.



Hence, the gcd(33,\:280)=1.



We now express this gcd of 1 as a linear combination of  33 and 280.



We can achieve this by making all the non zero remainders the subject and making a backward substitution.



1=33-2\times 16--(1)



16=280-33\times8--(2)



Equation (2) in equation (1) gives,



1=33-2\times (280-8\times33)



1=33-2\times 280+16\times33



1=17\times33-2\times 280



The above linear combination tells us that  17 is the inverse of 33.



Now we multiply both sides of our congruence relation by 17.



17\times 33x \equiv 17\times 38(mod\:280)



This implies that;



x \equiv 646(mod\:280)



x \equiv 86.



Since this is modulo, the solution is not unique because any integral addition or subtraction of the modulo (280 in this case) produces an equivalent solution.



Therefore the general solution is,



86+280n, where n is an  integer

6 0
4 years ago
Read 2 more answers
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