Question

The sum of three consecutive integers is 141. what is the smallest integer

Answer 1

Integer 1 = n
integer 2 = n + 1
integer 3 = n + 2

n + (n + 1) + (n + 2) = 141
3n + 3 = 141
3n = 141 - 3
3n = 138
n = 138/3
n = 46 --(1st integer)

n + 1 = 46 + 1 = 47 --(2nd integer)
n + 2 = 46 + 2 = 48 --(3rd integer)

so the smallest integer is 46