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4 years ago

How does changing the frequency affect the energy of the wave

Physics

1 answer:

ohaa [14]4 years ago

4 0

Answer:

An increase in frequency causes an increase in energy and vice versa.

Explanation:

The frequency of a wave is the number of cycles produced per second. This means that a increase in frequency will lead to more cycles generated per second hence an increase in energy.

However a decrease in frequency will lead to a subsequent decrease in energy. For light waves, the energy can be gotten by the formula; E=hf

where E is energy, h is Planck's constant and f is frequency.

we can say from the formula that Energy is directly proportional to frequency.

in conclusion an increase in frequency will lead to an increase in energy.

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All of the alleles of a specific gene in a population make up the

horsena [70]

Answer:

The collection of all the genes and the various alternate or allelic forms of those genes within a population is called its gene pool.

4 0

3 years ago

Salmon often jump waterfalls to reach their

erik [133]

Answer:

6.35 m/s

Explanation:

The motion of the salmon is equivalent to that of a projectile, which consists of two independent motions:

- A horizontal motion with constant speed

- A vertical motion with constant acceleration ( $g=-9.8 m/s^2$ , acceleration of gravity)

The horizontal velocity of the salmon is given by:

$v_x = u cos \theta$

where

u = ? is the initial speed

$\theta=32^{\circ}$ is the angle of projection

Then the horizontal distance covered by the salmon after a time t is given by

$d=v_x t =(u cos \theta) t$

Or equivalently, the time taken to cover a distance d is

$t=\frac{d}{u cos \theta}$ (1)

Along the vertical direction, the equation of motion is

$h = (u sin \theta) t + \frac{1}{2}gt^2$ (2)

where

$u sin \theta$ is the initial vertical velocity

If we substitute (1) into (2), we get:

$h = (u sin \theta) \frac{d}{cos \theta} + \frac{1}{2}g(\frac{d}{ ucos \theta})^2=d tan \theta + \frac{gd^2}{2u^2 cos^2 \theta}$

We now that in order to reach the breeding grounds, the salmon must travel a distance of

d = 2.02 m

reaching a height of

h = 0.574 m

Substituting these data into the equation and solving for u, we find the initial speed that the salmon must have:

$u =\sqrt{ \frac{gd^2}{2(h-d tan \theta) cos^2 \theta}}=\sqrt{\frac{(-9.8)(2.02)^2}{2(0.574-(2.02)(tan 32))(cos^2(32))}}=6.35 m/s$

8 0

3 years ago

The waves with the lowest energy and lowest frequencies of the electromagnetic spectrum are the

Andru [333]

<span>The waves with the lowest energy and lowest frequencies of the electromagnetic spectrum are the "Radio waves"

So, option B is your answer

Hope this helps!
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5 0

4 years ago

You considered the situation of moving a couch at a constant speed. You concluded that to move the couch at a constant speed, yo

Dmitry [639]

Answer:

The couch will remain stationary

Explanation:

Friction is the force that resist/opposes the motion. It is the force that has to e overcome before an object can move.

Since the frictional force of 50 N is required before the couch can move, applying 25 N can not overcome the frictional force of 50 N, so the couch will remain stationary.A force greater than 50 will be require to set the couch in motion

8 0

4 years ago

A constant force moves an object along the line segment from to . Find the work done if the distance is measured in meters and t

vladimir2022 [97]

This question is incomplete, the complete question is;

Flag

A constant force F = 6i+8j-6k moves an object along a straight line from point (6, 0, -10) to point (-6, 7, 2).

Find the work done if the distance is measured in meters and the magnitude of the force is measured in newtons.

Answer:

the work done is -88 J

Explanation:

Given the data in the question;

we know that;

Work done = F × S

where constant force F = ( 6i + 8j - 6k )

S = ( -6i + 7j + 2k ) - ( 6i + 0j - 10k )

S = ( (-6i - 6i) + (7j - 0j) + ( 2k - ( -10k) ) )

S = ( -12I + 7j + 12k )

Work force = ( 6i + 8j - 6k ) × ( -12I + 7j + 12k )

Work force = ( 6 × -12 ) + ( 8 × 7 ) + ( -6 × 12 )

Work force = -72 + 56 - 72

Work force = -88 J

Therefore, the work done is -88 J

8 0

3 years ago