It's a corrupted and un-proofread description for "scientist".
Answer:
Hey there
Your answer should be Joules, Watts, and J/s.
The joule
The joule (pronounced jool) is a derived unit of energy in the International System of Units. It is equal to the energy transferred to (or work done on) an object when a force of one newton acts on that object in the direction of the force's motion through a distance of one metre (1 newton-metre or N⋅m). It is also the energy dissipated as heat when an electric current of one ampere passes through a resistance of one ohm for one second. It is named after the English physicist James Prescott Joule (1818–1889).
The Watt
The watt (symbol: W) is a unit of power or radiant flux. In the International System of Units (SI), it is defined as a derived unit of (in SI base units)[1][2] 1 kg⋅m2⋅s−3 or, equivalently,[3] 1 joule per second (J/s). It is used to quantify the rate of energy transfer. The watt is named after James Watt (1736-1819), an 18th-century Scottish inventor.
I beg your parden
If I am correct may I please have the brainly
A device that detects small current differences and prevents electrocution that is often required as a safety measure for bathroom, kitchen, and exterior outlets is referred to as: Ground-fault interrupter.
<h3>What are
arc-fault circuit interrupter?</h3>
According to "Article 100 Arc-Fault Circuit interrupter (AFCI)," arc-fault circuit interrupter is an electrical device which is designed and developed to deenergize the electrical circuit whenever it detects and recognizes characteristics unique to arcing.
Similarly, a ground-fault interrupter simply refers to an electrical device that is designed and developed for the detection of small current differences in an electrical circuit.
The main purpose of a ground-fault interrupter is to prevent electrocution or electrical shock and as such, it is an important safety measure for the following areas in a building:
- Bathroom
- Kitchen
- Exterior outlets
Read more on ground-fault interrupter here: brainly.com/question/12615861
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Answer:
the image is virtual and erect and the lens divergent; therefore the correct answer is C
Explanation:
In a thin lens the magnification given by
m = h '/ h = - q / p
where h ’is the height of the image, h is the height of the object, q is the distance to the image and p is the distance to the object.
It indicates that the object is straight and is placed at a distance p> f
analyze the situation tells us that the magnification is positive so the distance to the image must be negative, that is, that the image is on the same side as the object.
Consequently the lens must be divergent
The magnification value is
0.4 = h ’/ h
h ’= 0.4 h
therefore the erect images
therefore the image is virtual and erect and the lens divergent; therefore the correct answer is C
