1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mamaluj [8]
3 years ago
5

Imagine a gene pool in a random-mating population. The frequency of allele b1 is 0.4; the frequency of allele b2 is 0.6. What is

the predicted frequency of heterozygotes among the offspring?
Physics
1 answer:
dangina [55]3 years ago
6 0

Answer:

0.48

Explanation:

Given that

Frequency b1=0.4

Frequency b2=0.6

The predicted frequency of heterozygotes is given as

f(b1b2)= 2 b1 x b2

Now by putting the values

f(b1b2)= 2 b1 x b2

f(b1b2)= 2 x 0.4 x 0.6

f(b1b2)=0.48

So the answer is 0.48.

You might be interested in
Which of the following is a sign of puberty?
umka2103 [35]
I would say D. all of the above
8 0
3 years ago
Read 2 more answers
A curved, transparent object used to refract light
zlopas [31]
It's called a concave lens.
6 0
3 years ago
Someone help me?
kap26 [50]

Answer:

-27.3 m/s

Explanation:

Given:

y₀ = 38 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: v

v² = v₀² + 2a (y − y₀)

v² = (0 m/s)² + 2 (-9.8 m/s²) (0 m − 38 m)

v = -27.3 m/s

Or, you can solve with energy.

PE = KE

mgh = ½ mv²

v² = 2gh

v = -27.3 m/s

3 0
3 years ago
Three resistors of 4.0, 6.0, and 10.0 Ω are connected in parallel. If the combination is connected in series with a 12.0-V batte
Grace [21]

Answer:

0.536 A

Explanation:

From the question,

The combined resistance of the parallel connection is given as

1/Rt = 1/4+1/6+1/10

Rt = 120/15

Rt = 8 ohms.

Since the the combination is connected in series with a 10 ohms resistor,

Rt' = 8+10 = 18 ohms.

Current flowing through the series circuit

I = V/Rt'

V = 12 V, Rt' = 18 ohms

I = 12/18

I = 0.67 A.

Therefore voltage across the combined resistor

V' = 8(0.67)

v' = 5.36 V.

Since the resistors a connected in parallel, the same voltage drop across them.

Therefore, current through the 10 ohms

Ix = 5.36/10

Ix = 0.536 A

5 0
3 years ago
A 86 kg human stands on the surface of Venus. The mass of Venus is 4.9 × 1024 kg and its radius is 6.1 × 106 m. Collapse questio
iris [78.8K]

Answer:

755.37 N

Explanation:

We are given that

Mass of venus=m_1=4.9\times 10^{24}kg

Radius=r=6.1\times 10^6m

Mass of human=m_2=86 kg

We know that the gravitational force between two bodies

F=G\frac{m_1m_2}{r^2}

Where G=Gravitational constant=6.67\times 10^{-11}Nm^2/kg^2

Using the formula

The magnitude of the gravitational force exerted by Venus on the human=F=\frac{6.67\times 10^{-11}\times 86\times 4.9\times 10^{24}}{(6.1\times 10^6)^2}

The magnitude of the gravitational force exerted by Venus on the human=F=755.37N

7 0
3 years ago
Other questions:
  • An object thrown vertically upward from the surface of a celestial body at a velocity of 36 ​m/s reaches a height of sequalsminu
    6·1 answer
  • Do you think it would be possible to compress a gas to zero volume
    6·2 answers
  • PLS HELP!!! A 1200-kg whale swims horizontally to the right at a speed of 6.0 m/s. It suddenly collides directly with a stationa
    13·1 answer
  • Describe factors than can make dishes in restaurants have variable nutritional values
    8·1 answer
  • What is the strength of the electric field 0.020 m from a 12 µC charge?
    11·1 answer
  • Two blocks, stacked one on top of the other, slide on a frictionless horizontal surface. The surface between the two blocks is r
    13·1 answer
  • A closed loop conductor that forms a circle with a radius of 1 m is located in a uniform but changing magnetic field. If the max
    8·1 answer
  • How much work does a 120 watt motor perform for 300 seconds?
    11·1 answer
  • Which task would a colorectal surgeon perform?
    12·1 answer
  • When you measure the mass of an object you are also measuring its what
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!