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saw5 [17]
3 years ago
10

The sum of two consecutive integers is -49. Write an equation that models this situation and find the values of the two integers

.
Mathematics
2 answers:
jeka57 [31]3 years ago
4 0

Answer:

n + n + 1 = –49; n = –25; n + 1 = –24

Step-by-step explanation:


IrinaK [193]3 years ago
3 0
-25 and -24

You can find this using the equation below:

x + (x + 1) = -49

Solve for x 
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A beautician sees clients each day to paint full sets of nails. The function g(x) represents the number of finger nails painted,
lions [1.4K]

Yes, the input and output are both possible.

Reason~

Given that the possible solution is (20,20),

<u>Input</u> = x = 20

<u>Output</u> = x = 20

Thus, g(20) = 20, which is clearly possible.

<em>Hope this helps :)</em>

7 0
3 years ago
Read 2 more answers
Water flows through pipe at a rate of 490 Milliliters every 6.5 hours express this rate of flow influence one's permanent round
likoan [24]

Answer:

To the nearest hundredth, the rate of flow will be 75.38 mm/hr

Step-by-step explanation:

Here in this case, we are to express the rate at which the water flow and round it up to the nearest hundredth.

We are told that water flows through the pipe at a rate of 490 mm every 6.5 hours.

Now, the rate will be 490/6.5 = 75.384615384615 mm/hr

Rounding this value to the nearest hundredth, we have 75.38 mm/hr

7 0
3 years ago
Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (
Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

P(\frac{T}{S}) = 0.95

P(\frac{T}{S^c}) = 0.05

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

P(S^c) =  1 - P(S)

= 1 - 0.3

= 0.7

ii. P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}

= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }

= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}

= 0.8906

iii. P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}

= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }

= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}

= 0.0221

We simply applied the above formulas so that the each part could come

8 0
3 years ago
Evaluate 4x^3 +2 for x= -1
padilas [110]

4x³+2

4(-1)³+2

(4 * -1) +2

-4+2 = -2


7 0
3 years ago
Someone can help me ?
tino4ka555 [31]
(3,-1) not sure tho I’d have to have a graph infront of me
4 0
3 years ago
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