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Maru [420]
3 years ago
13

The 199.99 digital camera any purchase was on sale for 15% off what amount did Annie get out the price

Mathematics
2 answers:
erastovalidia [21]3 years ago
5 0

Answer:

The discount is 30

169.99 is the price she will pay

Step-by-step explanation:

First find the discount

199.99 * 15%

199.99 * .15

29.9985

Rounds to 30.00

The discount is 30

199.99 - 30

169.99 is the price she will pay

Paraphin [41]3 years ago
4 0

Answer: About $30 less than the original price

Step-by-step explanation: 199.99x1.15 gives you 229.9885 and when you subtract 199.99 from that you get 29.9985 which is about 30 dollars.

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How to solve -18=6y+6(1+3y)
slamgirl [31]

Answer:-1

Step-by-step explanation:

I rewrote it so it looks like this:

6y+6(1+3y)=-18

6y+6(1)+6(3y)=-18

6y+6+18y=-18

24y+6=-18

     <u> -6   -6</u>

<u>24y</u>=<u>-24</u>

24      24

y=-1

6 0
4 years ago
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The original pulse rates are measure with units of​ "beats per​ minute". what are the units of the corresponding z​ scores? choo
posledela
the complete question is

 Pulse rates of women are normally distributed with a mean of 77.5 beats per minute and a standard deviation of 11.6 beats per minute. The original pulse rates are measure with units of "beats per minute". What are the units of the corresponding z scores? Choose the correct choice below.

A. The z scores are measured with units of "beats per minute."

B. The z scores are measured with units of "minutes per beat."

C. The z scores are measured with units of "beats."

D. The z scores are numbers without units of measurement.

we know that

A z-score is the number of standard deviations from the mean a data point is. But more technically it’s a measure of how many standard deviations below or above the population mean a raw score is

The z scores are numbers without units of measurement

therefore

the answer is the option D

8 0
3 years ago
Evaluate 2(x+4)^2 - (3y+5)^3 for x= -3 and y= -1
UNO [17]
<span>2(x+4)^2 - (3y+5)^3
at x=-3 and y=-1

2(-3+4)^2 - ((3*-1)+5)^3
2 (1)^2 - (2)^3
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5 0
4 years ago
Use fundamental theorem of calculus to find derivative of the function LOOK AT PHOTO
kykrilka [37]

Let c > 0. Then split the integral at t = c to write

f(x) = \displaystyle \int_{\ln(x)}^{\frac1x} (t + \sin(t)) \, dt = \int_c^{\frac1x} (t + \sin(t)) \, dt - \int_c^{\ln(x)} (t + \sin(t)) \, dt

By the FTC, the derivative is

\displaystyle \frac{df}{dx} = \left(\frac1x + \sin\left(\frac1x\right)\right) \frac{d}{dx}\left[\frac1x\right] - (\ln(x) + \sin(\ln(x))) \frac{d}{dx}\left[\ln(x)\right] \\\\ = -\frac1{x^2} \left(\frac1x + \sin\left(\frac1x\right)\right) - \frac1x (\ln(x) + \sin(\ln(x))) \\\\ = -\frac1{x^3} - \frac{\sin\left(\frac1x\right)}{x^2} - \frac{\ln(x)}x - \frac{\sin(\ln(x))}x \\\\ = -\frac{1 + x\sin\left(\frac1x\right) + x^2\ln(x) + x^2 \sin(\ln(x))}{x^3}

8 0
2 years ago
In this problem we will be dealing with the probability density function (pdf) associated with a continuous random variable, X.
konstantin123 [22]

Answer:

b)\ 0.568

Step-by-step explanation:

Given

f(x) = 6x(1- x);\ 0 \le x \le 1

Required

P(0.3 < x < 0.7)

From the question, we have:

P(a < x < b) = \int\limits^b_a {f(x)} \, dx

So, we have:

P(0.3 < x < 0.7) = \int\limits^{0.7}_{0.3} {6x(1 - x)} \, dx

Open bracket

P(0.3 < x < 0.7) = \int\limits^{0.7}_{0.3} {6x - 6x^2} \, dx

Integrate

P(0.3 < x < 0.7) =  \frac{6x^2}{2} - \frac{6x^3}{3}}|\limits^{0.7}_{0.3}

P(0.3 < x < 0.7) =  3x^2 - 2x^3|\limits^{0.7}_{0.3}

Substitute 0.7 and 0.3 for x

P(0.3 < x < 0.7) =  (3*0.7^2 - 2*0.7^3) - (3*0.3^2 - 2*0.3^3)

Using a calculator, we have:

P(0.3 < x < 0.7) =  (0.784) - (0.216)

Remove brackets

P(0.3 < x < 0.7) =  0.784 - 0.216

P(0.3 < x < 0.7) =  0.568

3 0
3 years ago
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