Question

At 10:00 a.m. two planes leave an airport. If the northbound plane flies at 280 mph and the southbound at 320 mph, at what time will they be 1,000 miles apart?
Which equation can be used to solve for t, the time it takes the planes to be 1,000 miles apart?

280t + 320t = 1,000
320t - 280t = 1,000
280 + 320 = 1,000t

Answer 1

The answer is the first one 280t +320t =1000
and it wold take a hour and a half to an hour and forty-five minutes 

Answer 2

Answer:

280t + 320t = 1,000

Step-by-step explanation:

At 10:00 a.m. two planes leave an airport. If the northbound plane flies at 280 mph and the southbound at 320 mph

Let 't' be the time taken when they are 1000 miles apart

the northbound plane flies at 280 mph

Distance  = speed * time

distance covered by northbound plane D1= 280 * t= 280t

the southbound at 320 mph

distance covered by southbound plane D2=320 t

Distance is 1000 miles apart

D1 + D2= 1000

280t + 320t = 1,000