I got quite Of bit of answers out of this
Answer: i think its C. but find another source just in case.
Answer:
Need more details. Like the picture.
Explanation:
Answer:
a) The expected phenotype of the F1 plants is 100% RrBb, red kernels.
b) The expected phenotypic classes in the F2 are: 9:3:3:1
9/16 R-B-, 3/16 rrB-, 3/16 R-bb, 1/16 rrbb
Proportions 9:6:1.
9/16 Red kernel (R-B-), 6/16 Brown kernel (rrB- + R-bb), 1/16 White kernel (rrbb)
Explanation:
<u>Available data:</u>
- brown kernel: R-bb or rrB-
1º Cross) RRBB x rrbb
F1) 100% RrBb (red kernels)
2ºCross) RrBb x RrBb
Gametes) RB RB
Rb Rb
rB rB
rb rb
Punnet Square) RB Rb rB rb
RB RRBB RRBb RrBB RrBb
Rb RRBb RRbb RrBB Rrbb
rB RrBB RrBb rrBB rrBb
rb RrBb Rrbb rrBb rrbb
F2) Phenotypic classes:
<em>9/16 R-B-</em>
<em> 3/16 rrB-</em>
<em> 3/16 R-bb</em>
<em> 1/16 rrbb</em>
Phenotypic proportions:
<em>9/16 Red kernel (R-B-)</em>
<em> 6/16 Brown kernel (rrB- + R-bb)</em>
<em> 1/16 White kernel (rrbb) </em>
