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Nadya [2.5K]
4 years ago
10

At what latitudd is the coriolis effect the smallest

Physics
1 answer:
alexandr1967 [171]4 years ago
6 0
The Coriolis effect is strongest at the north and south poles, and zero on the equator (zero latitude).
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A uniform disk of mass M and radius R has rotational inertia about its central axis of Idisk = 1/2 MR2. A uniform rod of mass m
expeople1 [14]

Answer:

5/6 MR²

Explanation:

In the composite object, the distance from the disk's axis to the rod's axis is R/2.  Using parallel axis theorem, the rod's new moment of inertia is:

I = 1/12 MR² + M (R/2)²

I = 1/12 MR² + 1/4 MR²

I = 1/3 MR²

The total moment of inertia is therefore:

I = 1/2 MR² + 1/3 MR²

I = 5/6 MR²

4 0
4 years ago
Why does a rolling sphere slows down?​
VLD [36.1K]

The sphere slow down due to friction force between the surface of the sphere and the surface on that the sphere is rolling . The friction force acting against the motion of the sphere. Thats why it is slowed down. In fact not only a sphere, anything can not slow down untill a force act against it's motion.

3 0
3 years ago
Read 2 more answers
20 points please answer
Anna [14]
Another way to test your question is to build your own miniature buildings. Depending on how in-depth you go, building could get a little pricey, but if you keep it basic there shouldn't be a problem. Decide on a certain number of foundations to test [maybe 3 or so] and try simulating an earthquake. 
<span>Hope this helps! </span>
6 0
3 years ago
a runner goes around a 1 mile track if they end up at their starting position what is their distance traveled
Evgesh-ka [11]

Answer:

1 mile

Explanation:

The distance travelled is the length of the path that the runner traveled.

As you have stated he has traveled a 1 mile track so the length he traveled is 1 mile.

The point of ending matters only in displacement not in distance. In displacement we measure the unidirectional shortest distance between two points where the displacement in this case is 0.

3 0
3 years ago
A spherical steel ball bearing has a diameter of 2.540 cm at 20.00°C. (Assume the coefficient of linear expansion for steel is 1
shusha [124]

Answer:

(a) 2.542 cm

(b) 272.7°C

Explanation:

diameter, d = 2.540 cm

T1 = 20°C

α = 11 x 10^-6 /°C

(a) Let d' be the diameter.

T2 = 87°C

Use he formula for the areal expansion

A' = A ( 1 + βΔT)

where, β is the coefficient of areal expansion and ΔT is teh rise in temperature, A' be the area at high temperature and A be the area at low temperature.

β = 2 α = 2 x 11 x 106-6 = 22 x 10^-6 /°C

So,

\frac{\pi D'^{2}}{4}=\frac{\pi D^{2}}{4}\left ( 1+\beta \Delta T \right )

D'^2 = 2.54^2 ( 1 + 22 x 10^-6 x 67)

D' = 2.542 cm

(b) Let the change in temperature is ΔT.

Use the formula for the volumetric expansion

ΔV = V x γ x ΔT

Where, γ = 3 x α = 3 x 11 x 10^-6 = 33 x 10^-6 /°C

0.9/100 = 33 x 10^-6 x ΔT

ΔT = 272.7°C

6 0
3 years ago
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