1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
cricket20 [7]
3 years ago
7

In a perfectly elastic collision between two perfectly rigid objects

Physics
1 answer:
ipn [44]3 years ago
7 0

Both the total momentum and the total kinetic energy are conserved

Explanation:

- In a collision between two or more objects, if there are no external forces acting on the system (isolated system), the total momentum of the objects is always conserved. This is called principle of conservation of momentum, and can be written as follows:

mu+MU = mv+MV

where

m, M are the masses of the two objects

u, U are the initial velocities of the two objects

v, V are the final velocities of the two objects

- The total kinetic energy, however, is not always conserved. In fact, we have two types of collision:

1) In a perfectly elastic collision, the total kinetic energy of the objects is conserved. This means that we can write the following equation:

\frac{1}{2}mu^2 + \frac{1}{2}MU^2 = \frac{1}{2}mv^2+\frac{1}{2}MV^2

2) In an inelastic collision, the total kinetic energy of the object is NOT conserved. This means that part of the total kinetic energy is "lost", converted into other forms of energy (mainly thermal energy, due to the presence of frictional forces within the system). The most extreme case is called perfectly inelastic collision, in which the two objects stick together after the collision, and there is the maximum loss of kinetic energy.

Learn more about collisions:

brainly.com/question/13966693#

brainly.com/question/6439920

LearnwithBrainly

You might be interested in
During a tennis volley, a ball that arrives at a player at 40 m/s is struck by the racquet and returned at 40 m/s. The other pla
Butoxors [25]

Answer:Racquet force is twice of Player force

Explanation:

Given

ball arrives at a speed of u=-40\ m/s

ball returned with speed of v=40\ m/s

average Force imparted by racquet on the ball is given by

F_{racquet}=\frac{m(v-u)}{\Delta t}

where m=mass\ of\ ball

\Delta t=time of contact of ball with racquet

F_{racquet}=\frac{m(40-(-40))}{\Delta t}

F_{racquet}=\frac{80m}{\Delta t}-----1

When it land on the player hand its final velocity becomes zero and time of contact is same as of racquet

F_{player}=\frac{m(0-40)}{\Delta t}

F_{player}=\frac{-40m}{\Delta t}-----2

From 1 and 2 we get

F_{racquet}=-2F_{player}

Hence the magnitude of Force by racquet is twice the Force by player

5 0
3 years ago
Name three bright Saturn ring features, and explain why they are so bright.
Leviafan [203]

The F Ring, the Cassini Division, and the C Ring are bright ring features. They are bright due to the low concentration of materials within them, which allows sunlight to shine through.


6 0
3 years ago
Opal adds 25 grams of salt to a one-liter glass beaker filled up to its volume mark with pure water. She stirs the water until t
Mars2501 [29]

By what i know i think that the answer would be A a homogeneous mixture.

5 0
3 years ago
Coherent light of frequency 6.37×1014 Hz passes through two thin slits and falls on a screen 88.0 cm away. You observe that the
IgorC [24]

Answer:

The distance between the two slits is 40.11 μm.

Explanation:

Given that,

Frequency f= 6.37\times10^{14}\ Hz

Distance of the screen l = 88.0 cm

Position of the third order y =3.10 cm

We need to calculate the wavelength

Using formula of wavelength

\lambda=\dfrac{c}{f}

where, c = speed of light

f = frequency

Put the value into the formula

\lambda=\dfrac{3\times10^{8}}{6.37\times10^{14}}

\lambda=471\ nm

We need to calculate the distance between the two slits

m\times \lambda=d\sin\theta

d =\dfrac{m\times\lambda}{\sin\theta}

Where, m = number of fringe

d = distance between the two slits

Here, \sin\theta =\dfrac{y}{l}

Put the value into the formula

d=\dfrac{3\times471\times10^{-9}\times88.0\times10^{-2}}{3.10\times10^{-2}}

d=40.11\times10^{-6}\ m

d = 40.11\ \mu m

Hence, The distance between the two slits is 40.11 μm.

7 0
3 years ago
When an electric current flows through a long conductor, each free electron moves
ki77a [65]
A. through a relatively short distance.

The speed is actually called the drift speed of the electron.
7 0
3 years ago
Other questions:
  • Classify each of the following items as a rigid body, a system of rigid bodies, or a nonrigid body:
    6·1 answer
  • The phrase all men are created equal is from what document
    6·1 answer
  • Later that day, Martin does the same thing with Josh, who is 2 times heavier than Martin. If the collision is totally inelastic,
    8·1 answer
  • If you are in an airplane. you look out the window and the clouds appear to be moving. what is your frame of reference?
    7·1 answer
  • What is the inverse tangent of 0.9?
    8·2 answers
  • The ball's gravitational potential energy as a function of its height after release. The ball's kinetic energy as a function of
    7·1 answer
  • Which of the following ocean-floor features would contain the newest rocks?
    9·2 answers
  • Rest and motion are relative terms. write in brief​
    5·1 answer
  • Chang wants to build a circuit that will light up the bulb from a flashlight. Which component could Chang leave out and still li
    12·2 answers
  • Obtain a volume of 12.5 millimeters of liquid in the diagram
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!