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natima [27]
2 years ago
9

Use the distributive property to solve the following 4(4a+6b)

Mathematics
1 answer:
Alina [70]2 years ago
6 0

4(4a+6b) =16a+24b

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The swimming pool and the floor of your gym are similar in size. The pool is 75 feet long by 60 feet wide. What are possible dim
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From the facts given, the swimming pool and the floor of the gym has the same in size. The pool has a dimension of 75 ft by 60 ft. Basically, the possible size of the gym floor is also 75 ft by 60 ft. 
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Allen has $10 to spend. He bought a sandwich for
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Answer:

MY friend the anwser is A  I hope this will help plz mark me brainliest

Step-by-step explanation:

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2 years ago
This year the fifth grade collected 216 fewer plastic containers than the fourth grade.How many plastic containers did the fifth
kap26 [50]

Let number of plastic containers collected by fourth grade= x

Then number of plastic containers collected by fifth grade students=x-216

OR

If number of plastic container collected by fifth grade is y

then number of plastic container collected by fourth grade=y+216

So, we can write it as follows

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7 0
3 years ago
Which situation is most likely to show a constant rate of change?
Wewaii [24]
Probably d as the the temperature outside is unpredictable and the we know the time is always going up
6 0
2 years ago
Please help me with both questions!!!!​​
Naya [18.7K]

Answer:

Step-by-step explanation:

16.

points are (0,-3),(2,1),(4,-3)

eq. of line through (0,-3) and (2,1) is

y+3=\frac{1+3}{2-0}(x-0)

or y+3=2x

2x-y=3

as the line is dotted so either < or >.

consider 2x-y>3

put x=0,y=0

0>3

which is not possible .

(0,0) does not satisfy the inequality

Hence shaded region is the required region.

now eq of line through (2,1)and (4,-3) is

y-1=\frac{-3-1}{4-2}(x-2)

y-1=-2(x-2)

y-1=-2x+4

2x+y=5

it is also a  dotted line so either < or >

consider 2x+y<5

put x=0,y=0

0<5

which is true.

so (0,0) satisfy this inequality.

so the two inequalities are

2x-y>3

and 2x+y<5

17.

consider the points (0,4),(2,3),(4,4)

eq. of line through (0,4) and (2,3) is

y-4=\frac{3-4}{2-0}(x-0)

y-4=-1/2(x)

2y-8=-x

or x+2y=8

as the line is solid

so either≤ or ≥

consider x+2y≥8

put x=0,y=0

0≥8

which is impossible.

(0,0) does not satisfy the graph.

which is true as graph lies above the line.

again eq. of line through (2,3) and (4,4) is

y-3=\frac{4-3}{4-2}(x-2)

y-3=1/2(x-2)

2y-6=x-2

x-2y=-4

consider x-2y≤-4

put x=0, y=0

0≤-4

which is impossible.

so (0,0) does not satisfy the graph.

so inequality is true as shaded portion is above and left of the line.

so two inequalities are

x+2y≥ 8

and x-2y≤-4

5 0
3 years ago
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