All categories

3 years ago

What is the quantity of 26/13

Mathematics

2 answers:

kirill [66]3 years ago

8 0

It would be any quantity that reduces to the value 2.

For example,

26/13 = 18/9 = 38/19 = 2pi / pi = 6/3 = -10 / -5 = ...... = 2

yan [13]3 years ago

4 0

Answer:

the quantity is 2

Step-by-step explanation:

26/13=2

You might be interested in

What is the surface area of this rectangular prism?

Sloan [31]

C) 198m^2

(6*3*2) + (6*9*2) + (3*9*2) = 198 and that accounts for all the sides

3 0

3 years ago

You can use a system of equations to graph and solve the polynomial equation 3x3 + x= 2x2 + 1. Which statement is true?

Nina [5.8K]

Answer:

The y-coordinates of the solutions to the system and the zeros of the equation are not equal

Step-by-step explanation:

7 0

3 years ago

There are 4 pieces of paper, numbered 10 to 13, in a hat. After another numbered piece of paper is added, the probability of pic

yKpoI14uk [10]

Answer: The fifth piece of paper could have any number 9 and less or 14 and greater.

Step-by-step explanation: The list of choices is not given in the question, but it makes sense that the new number would not be a duplicate of any of the numbers 10, 11, 12, 13. Otherwise that would change the probability to 5/5.

So any other number could be a possibility.

5 0

3 years ago

"is it appropriate to use the normal approximation for the sampling distribution of"

Katyanochek1 [597]

Answer: Normal approximation can be used for discrete sampling distributions, such as Binomial distribution and Poisson distribution if certain conditions are met.

Step-by-step explanation: We will give conditions under which the Binomial and Poisson distribitions, which are discrete, can be approximated by the Normal distribution. This procedure is called normal approximation.

1. Binomial distribution: Let the sampling distribution be the binomial distribution $B(n,p)$ , where $n$ is the number of trials and $p$ is the probability of success. It can be approximated by the Normal distribution with the mean of $np$ and the variance of $np(1-p)$ , denoted by $N(np,np(1-p))$ if the following condition is met:

$n>9\left(\frac{1-p}{p}\right)\text{ and } n>9\left(\frac{p}{1-p}\right)$

2. Poisson distribution: Let the sampling distribution be the Poisson distribution $P(\lambda)$ where $\lambda$ is its mean. It can be approximated by the Normal distribution with the mean $\lambda$ and the variance $\lambda$ , denoted by $N(\lambda,\lambda)$ when $\lambda$ is large enough, say $\lambda>1000$ (however, different sources may give different lower value for $\lambda$ but the greater it is, the better the approximation).

5 0

3 years ago

Use completing the aquare to solve for x in the equation (x+7)(x-9)=25

Tema [17]

Answer:

x = 1 + sqrt(89) or x = 1 - sqrt(89)

Step-by-step explanation:

Solve for x:

(x - 9) (x + 7) = 25

Expand out terms of the left hand side:

x^2 - 2 x - 63 = 25

Add 63 to both sides:

x^2 - 2 x = 88

Add 1 to both sides:

x^2 - 2 x + 1 = 89

Write the left hand side as a square:

(x - 1)^2 = 89

Take the square root of both sides:

x - 1 = sqrt(89) or x - 1 = -sqrt(89)

Add 1 to both sides:

x = 1 + sqrt(89) or x - 1 = -sqrt(89)

Add 1 to both sides:

Answer: x = 1 + sqrt(89) or x = 1 - sqrt(89)

7 0

3 years ago